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grigory [225]
2 years ago
15

Suppose 8 out of every 20 students are absent from school less than five (5) days a year. Predict how many students would be abs

ent from school less than five (5) days a year out of 40,000 students
Mathematics
2 answers:
nikklg [1K]2 years ago
6 0
Yes yes it is ok mhm
Zolol [24]2 years ago
4 0

Answer:

the answer is 16,000 students

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Consider the circle of radius 5 centered at (0, 0). Find an equation of the line tangent to the circle at the point (3, 4) in sl
Wittaler [7]

Answer:

\displaystyle y= -\frac{3}{4} x + \frac{25}{4}.

Step-by-step explanation:

The equation of a circle of radius 5 centered at (0,0) is:

x^{2} + y^{2} = 5^{2}.

x^{2} + y^{2} = 25.

Differentiate implicitly with respect to x to find the slope of tangents to this circle.

\displaystyle \frac{d}{dx}[x^{2} + y^{2}] = \frac{d}{dx}[25]

\displaystyle \frac{d}{dx}(x^{2}) + \frac{d}{dx}(y^{2}) = 0.

Apply the power rule and the chain rule. Treat y as a function of x, f(x).

\displaystyle \frac{d}{dx}(x^{2}) + \frac{d}{dx}(f(x))^{2} = 0.

\displaystyle \frac{d}{dx}(2x) + \frac{d}{dx}(2f(x)\cdot f^{\prime}(x)) = 0.

That is:

\displaystyle \frac{d}{dx}(2x) + \frac{d}{dx}\left(2y \cdot \frac{dy}{dx}\right) = 0.

Solve this equation for \displaystyle \frac{dy}{dx}:

\displaystyle \frac{dy}{dx} = -\frac{x}{y}.

The slope of the tangent to this circle at point (3, 4) will thus equal

\displaystyle \frac{dy}{dx} = -\frac{3}{4}.

Apply the slope-point of a line in a cartesian plane:

y - y_0 = m(x - x_0), where

  • m is the gradient of this line, and
  • (x_0, y_0) are the coordinates of a point on that line.

For the tangent line in this question:

  • \displaystyle m = -\frac{3}{4},
  • (x_0, y_0) = (3, 4).

The equation of this tangent line will thus be:

\displaystyle y - 4 = -\frac{3}{4} (x - 3).

That simplifies to

\displaystyle y= -\frac{3}{4} x + \frac{25}{4}.

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3 years ago
James had a business mowing lawns for $25 per lawn and raking leaves for $0.75 per pile. His goal is to earn exactly $37 each ti
Marizza181 [45]

Answer:

Step-by-step explanation:

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3 years ago
If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
Lelu [443]
Hello : 
<span>If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
</span>(f+g)(x)= f(x) +g(x) = x/2-2  +2x²+x-3 = x/2 +2x²+x-5
(f+g)(x)= (x+4x²-2x-10) /2
(f+g)(x)= (4x²+3x-10)/2 = 2x²+3/2 x -5
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3 years ago
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Can someone help me, please
shepuryov [24]

Answer:

yes... 13.3

Step-by-step explanation:

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3 years ago
The product of a number and 9 is -450
Softa [21]

Answer:

-50

Well to get the answer of the product of a number and 9 is -450. You must divide 9 by -450 using long divison.

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