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sergeinik [125]
3 years ago
8

If two integers are positive, the one closer to zero is_________greater

Mathematics
1 answer:
finlep [7]3 years ago
5 0

Answer:  C) Never

If two integers are positive, the one closer to zero is <u>  never  </u> greater.

An example would be something like the integers 3 and 5. The value 3 is closer to zero, so it's not greater than 5. Stuff on the left is smaller than stuff on the right.

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Your round-trip drive to work is 4 times 3 divided 10 miles. How many miles do you drive to and from work in 3 days?
anygoal [31]

Answer:

okay here is what i think see if my explanation will help

Step-by-step explanation:

i think

(4*3/10)*3 get it just follow this work it out and tell me your answer

7 0
3 years ago
I need help due today at 6
Fofino [41]

Answer:


Step-by-step explanation:


3 0
3 years ago
Simplify the expression below.<br> 8(4x+1)−18x−5
Jet001 [13]

Answer:

14 times +3

Step-by-step explanation:

also srry could not find the sign for times (:

4 0
3 years ago
Read 2 more answers
Carlos and Ana were asked to find an explicit formula for the sequence -10,-4,2,8,...−10,−4,2,8,...Minus, 10, comma, minus, 4, c
mars1129 [50]

Answer:

Ana is correct

Step-by-step explanation:

Given

Sequence:\ -10, -4, 2,8

Carlos; f(n) = -10 + 6n

Ana; f(n) = -10 + 6(n-1)

Required

Determine who is right?

To do this, we simply test each sequence.

For Carlos:

When n = 1

f(1) = -10 + 6 * 1 = -10 + 6 = -4

When n = 2

f(2) = -10 + 6 * 2 = -10 + 12 = 2

<em>This is incorrect because the first and second term of the sequence are -10 and -4 not -4 and 2</em>

<em></em>

For Ana:

When n = 1

f(1) = -10 + 6(1-1) = -10 + 6*0 = -10 + 0 = -10

When n = 2

f(2) = -10 + 6(2-1) = -10 + 6*1 = -10 + 6 = -4

When n=3

f(3) = -10 + 6(3-1) = -10 + 6*2 = -10 + 12 = 2

When n = 4

f(4) = -10 + 6(4-1) = -10 + 6*3 = -10 + 18 = 8

This is correct.

<em>Hence, Ana is correct</em>

8 0
3 years ago
Read 2 more answers
Each cone of the hourglass has a height of 18 millimeters . the total height of the sand within the top portion of the hour glas
statuscvo [17]
Let

Vco------------------- >Volume cone
Vcy------------------ >Volume cylinder 
r= 8mm
hco----------- > height of cone=18 mm
hcy------------ > height of cylinder =54-18=36 mm

then

Vco=π*r² *hco/3--------- > π*8² *18/3=π*384 mm³
Vcy=π*r² *hcy--------- > π*8² *36=π*2304 mm³

the total cubic millimeters of sand=Vco+Vcy=π*384+π*2304=π*2688

if 10π cubic millimeters --------------------- > 1 seg
π*2688--------------------------------- X

X=π*2688/10π=268.8 seg

the answer is 268.8 seg
5 0
4 years ago
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