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3 years ago

Solve for x. Round to the nearest tenth of a degree, if necessary PLEASE HELP I HAVE 10 MINS TILL ITS DUE

Mathematics

2 answers:

grigory [225]3 years ago

4 0

Answer:

x = 47.4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj / hyp

cos x = 8.8 / 13

Take the inverse cos of each side

cos ^-1 ( cos x) = cos ^-1( 8.8 /13)

x = cos ^-1( 8.8 /13)

x =47.39633319

Rounding to the nearest tenth

x =47.4

exis [7]3 years ago

3 0

Answer:

36.9 degrees

Step-by-step explanation:

using SOHCAHTOA we can see that we need to use cos because the sides that are given are the adjacent side and the hypotenuse so u have to divide the adjacent by the hypotenuse which is 8.8/13 and you should get 0.8 after you round to the nearest tenth and then you use your calculator to do cos^-1 (0.8) and you get 36.9 after you round to the nearest tenth of a degree

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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind

Gemiola [76]

Answer:

(a)

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

(b)

$1\ girl = \{GBB, BBG, BGB\}$

$P(1\ girl) = 0.375$

ii.

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

$P(Atleast\ 2 \ girls) = 0.5$

iii.

$No\ girl = \{BBB\}$

$P(No\ girl) = 0.125$

Step-by-step explanation:

Given

$Children = 3$

$B = Boys$

$G = Girls$

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

And the number of elements are:

$n(S) = 8$

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

$1\ girl = \{GBB, BBG, BGB\}$

And the number of the list is;

$n(1\ girl) = 3$

The probability is calculated as;

$P(1\ girl) = \frac{n(1\ girl)}{n(S)}$

$P(1\ girl) = \frac{3}{8}$

$P(1\ girl) = 0.375$

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

And the number of the list is;

$n(Atleast\ 2 \ girls) = 4$

The probability is calculated as;

$P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}$

$P(Atleast\ 2 \ girls) = \frac{4}{8}$

$P(Atleast\ 2 \ girls) = 0.5$

Solving (biii) No girl

From the list of possible elements, we have:

$No\ girl = \{BBB\}$

And the number of the list is;

$n(No\ girl) = 1$

The probability is calculated as;

$P(No\ girl) = \frac{n(No\ girl)}{n(S)}$

$P(No\ girl) = \frac{1}{8}$

$P(No\ girl) = 0.125$

7 0

3 years ago

If a+b=5 and a-b=4 then b^2-a^2 =

Anna007 [38]

Answer:

$a + b = 5 \\ a \: = 5 - b \\ a - b = 4 \\ 5 - b - b = 4 \\ 5 - 2b = 4 \\ 5 - 4 = 2b \\ 1 = 2b \\ \frac{1}{2} = \frac{2b}{2} \\0.5 = b \\ b = 0.5 \\ a = 5 - b \\ = 5 - 0.5 \\ = 4.5 \\ {a \: }^{2} - {b}^{2} = ( {4.5}^{2}) - ( {0.5}^{2} ) \\ = 20.25 - 0.25 \\ = 20 \\ {a}^{2} - {b}^{2} = 20$

Step-by-step explanation:

HOPE THAT THIS IS HELPFUL.

HAVE A GREAT DAY.

5 0

3 years ago

Nine increased by the product of a number and 2 is less than or equal to 27.

Naily [24]

Answer:

x≤9

Step-by-step explanation:

9+2x≤27

1) Subtract both sides by 9:

2x≤18

2) Divide both sides by 2:

x≤9

8 0

4 years ago

Complete the square than convert to vertex form. y=2x^2+8x-9

8_murik_8 [283]

$y=2x^2+8x-9\\D=b^2-4ac\\D=64-4(2)(-9)\\D=64+72 > 0$

There are 2 roots so the only way to complete the square is,

$y=2x^2+8x-9\\y=2[(x^2+4x)]-9\\y=2[(x^2+4x+4)-4]-9\\y=2[(x+2)^2-4]-9\\y=2(x+2)^2-8-9\\y=2(x+2)^2-17$

Just factor 2 out of 2x^2+8x (just ignore the -9) then find the number that will make the terms be able to complete the square.

then complete the square and multiply 2 inside the brackets.

subtraction as you already get the vertex form and know how to complete the square.

Vertex Form: $y=2(x+2)^2-17$

3 0

3 years ago

Can someone plz help? Only have a hour...I'll make crown the best and triple the points!!!

kykrilka [37]

Answer:

x= 3.57

Step-by-step explanation:

32 ( x + 2.5) = 114.24

32* x + 32* 2.5= 114.24

32x + 80= 114.24

-80 -80

32x= 114.24

/ 32 /32

x= 3.57

for the part that says convince me, we can use the eqution

/= divide

8 0

3 years ago