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3 years ago

I need help with this

Mathematics

2 answers:

xenn [34]3 years ago

7 0

-4,3 is the answer:)

pickupchik [31]3 years ago

5 0

The second one is the answer

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2. What is the volume of a box of cereal with the dimensions Shown? 2 in I Join rin

melamori03 [73]

Answer:

140 in

Step-by-step explanation:

To find the volume use the formula length x width x height

2 x 10 x 7= 140 in

8 0

3 years ago

Read 2 more answers

3) A local school district has 4512 students this year. The student population is declining by 2.5% per year. How many students

il63 [147K]

Answer:

Number of students(n1)= 4,402

Step-by-step explanation:

Giving the following information:

Number of students= 4,512

Declining rate= 2.5%

To calculate the number of students next year, we need to use the following formula:

Number of students (n+x)= number of students (n0) / [(1+declining rate)^(n+x)

x= number of years

Number of students(n1)= 4,512/1.025

Number of students(n1)= 4,402

5 0

3 years ago

Divide X^2+77x+20 by x+9 what is the quotient and remainder ?

adelina 88 [10]

X + 68 with a remainder of (-592)

5 0

4 years ago

The face of a clock has a circumference of 63 in. What is the area of the face of the clock?

ryzh [129]

Answer:

The area of the clock $= 315.41\ inch^{2}$

Step-by-step explanation:

We have been given the face of the clock that is $63\ in$

So that is also the circumference of the clock.

Since the clock is circular in shape.

So $2\pi(r)=63\ inch$

From here we will calculate the value of radius $(r)$ of the clock that is circular in shape.

Then $2\pi(r)=63\ inch =\frac{63}{2\pi} = 10.02\ in$

Now to find the area of the clock we will put this value of (r) in the equation of area of the circle.

Now $\pi (r)^{2}=\pi(10.02)^{2}=315.41\ in^{2}$

So the area of the face of the clock = $315.41\ in^{2}$

6 0

3 years ago

The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz

marishachu [46]

The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$ , then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$ .

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$ .

Answer: the second polynomial is $3yz^2-3z^2-5y+7$ .

3 0

3 years ago

Read 2 more answers