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salantis [7]
3 years ago
9

I need help with this

Mathematics
2 answers:
xenn [34]3 years ago
7 0
-4,3 is the answer:)
pickupchik [31]3 years ago
5 0
The second one is the answer
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2. What is the volume of a box<br>of cereal with the dimensions<br>Shown?<br>2 in<br>I Join<br>rin​
melamori03 [73]

Answer:

140 in

Step-by-step explanation:

To find the volume use the formula length x width x height

2 x 10 x 7= 140 in

8 0
3 years ago
Read 2 more answers
3) A local school district has 4512 students this year. The student population is declining by 2.5% per year. How many students
il63 [147K]

Answer:

Number of students(n1)= 4,402

Step-by-step explanation:

Giving the following information:

Number of students= 4,512

Declining rate= 2.5%

<u>To calculate the number of students next year, we need to use the following formula:</u>

Number of students (n+x)= number of students (n0) / [(1+declining rate)^(n+x)

x= number of years

Number of students(n1)= 4,512/1.025

Number of students(n1)= 4,402

5 0
3 years ago
Divide X^2+77x+20 by x+9 what is the quotient and remainder ?
adelina 88 [10]
X + 68 with a remainder of (-592)

5 0
4 years ago
The face of a clock has a circumference of 63 in. What is the area of the face of the clock?
ryzh [129]

Answer:

The area of the clock = 315.41\ inch^{2}

Step-by-step explanation:

We have been given the face of the clock that is 63\ in

So that is also the circumference of the clock.

Since the clock is circular in shape.

So 2\pi(r)=63\ inch

From here we will calculate the value of radius (r) of the clock that is circular in shape.

Then 2\pi(r)=63\ inch =\frac{63}{2\pi} = 10.02\ in

Now to find the area of the clock we will put this value of (r) in the equation of area of the circle.

Now \pi (r)^{2}=\pi(10.02)^{2}=315.41\ in^{2}

So the area of the face of the clock =315.41\ in^{2}

6 0
3 years ago
The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz
marishachu [46]

The first polynomial is y -4yz^2-3 and let the second polynomial be P(y,z).

If the sum of two polynomials is -yz^2-3z^2-4y+4, then y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4.

Take the first polynomial from the left side to the right side:

P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7.

Answer: the second polynomial is 3yz^2-3z^2-5y+7.

3 0
3 years ago
Read 2 more answers
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