A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 4 liters of a 50% iodine mixture?
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Let x = liters of 40% iodine
then
4-x = liters of 80% iodine
Using algebra:
.40x + .80(4-x) = .50(4)
.40x + 3.20-.80x = 2
3.20-.40x = 2
x = 4 liters (40% iodine)
80% iodine:
4-x = 4-4 = 0 liters needed (80% iodine)
Answer:
x = 6
Step-by-step explanation:
8x = 48,
Divide each side by 8 to isolate x
8x/8 = 48/8
x = 6
If I did the math right the answer should be 1,750
Simplify the expression.<span>1213</span>
Answer:
By using rules of triangle angles i found that x= 26°
Step-by-step explanation:
i used the rule that the interior angles of any triangle equal 180°
If we take the triangle which contains x, 28, 36, and 90 (the square in the corner idicates its a 90° angle) we can use the rule that the interior angles of any triangle equal 180. 36 + 90 gives 126 and x and 28 make up the same angle. 180-126 gives 54 meaning x and 28° add up to 54
54-28=26
x=26°
