Answer:
Determine the domain and range of the given function
1 answer:
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Answer:
The sample has not met the required specification.
Step-by-step explanation:
As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow
: The true average penetration is 50 mils
: The true average penetration is > 50 mils
Since we are trying to see if the true average is greater than 50, this is a right-tailed test.
If the <em>level of confidence</em> is α = 0.05 then the score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)
The z-score associated with this test is
where
= <em>mean of the sample</em>
= <em>average established by the specification</em>
s = <em>standard deviation of the sample</em>
n = <em>size of the sample</em>
Computing this value of z we get z = 3.42
Since z > we can conclude that the sample has not met the required specification.
Answer:
280 ft squared
Step-by-step explanation:
To find the area of the nonshaded portion, we can find the area of the entire floor and then subtract the shaded area.
The total area is that of a rectangle: 30 * 15 = 450 ft squared.
Now, the shaded region is made up of a rectangle and a triangle.
- The rectangle has length 8 and width 10, so its area is 10 * 8 = 80 ft squared.
- The triangle has base 12 and height 15, so using the area of a triangle formula: (where b is the base and h is the height) = (12 * 15)/2 = 180/2 = 90 ft squared.
- The total shaded region is: 80 + 90 = 170 ft squared
Subtract 110 from 450: 450 - 170 = 280 ft squared.
Thus, the answer is 280 ft squared.
Hope this helps!