Answer: 3r + 2b = 24
r + 3b = 16
Step-by-step explanation:
Let the red blocks be represented by r
Let blue blocks be represented by b
Since 3 red blocks and 2 blue blocks weigh 24 ounces. This will be:
3r + 2b = 24
1 red block and 3 blue blocks weigh 16 ounces. This will be:
r + 3b = 16
Therefore, the equation will be:
3r + 2b = 24
r + 3b = 16
Hi Timothy,
1.Which explains why the sequence 216, 12, 2/3 is arithmetic or geometric?
Answer - C.The sequence is geometric because it decreases by a factor of 1/18
The reason I chose C is the fact that the numbers go down greatly, and it has to to be geometric because when you are trying to solve the problem with arithmetic you don't get and exact rule for how to solve the problem.
M=123 degrees g=81 degrees f=99 degrees k=57 degrees q=81 degrees s=42 degrees h=123 degrees p=99 degrees r=57 degrees v=123 degrees u=57 degrees
A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)
The amount of sample that will remain after 4000 years is; 4.8357 mg
The number of years that it will take for only 17 mg of the sample to remain is; 1076 years
<h3>How to solve exponential decay function?</h3>
A) Using the model for radioactive decay;
m(t)= m₀e^(-rt)
where;
m₀ is initial mass
r is rate of growth
t is time
Thus, we are given;
m₀ = 27 mg
r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043
and so we have;
m(t) = 27e^(-0.00043t)
c) The amount that will remain after 4000 years is;
m(4000) = 27e^(-0.00043 * 4000)
m(4000) = 27 * 0.1791
m(4000) = 4.8357 mg
d) For 17 mg to remain;
17 = 27e^(-0.00043 * t)
17/27 = e^(-0.00043 * t)
In(17/27) = -0.00043 * t
-0.4626/-0.00043 = t
t = 1076 years
Read more about Exponential decay function at; brainly.com/question/27822382
#SPJ1
Minor Arc AC = 110 degrees (given)
As indicated in the hints,
OA=OC => OAC=OCA=(180-110)/2 = 35
Similarly,
OAB=OBA=(48-35)=13
=>
OBC=OCB=(180-35-35-13-13)/2=(180-96)/2=84/2=42
=>
Angle B = 13+42 = 55 degrees
Check:
55+55+35+35+13+13 = 180 degrees (angles of a triangle) ok.
