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lutik1710 [3]
3 years ago
15

Find a − b when a = −7 and b = 11.

Mathematics
1 answer:
Mariana [72]3 years ago
3 0

Answer:

-18

Explanation:

a - b

a = -7

b = 11

Insert -7 for 'a' and 11 for 'b'

-7 - 11

= -18

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which polynomials are in standard form? A. t^4-1 B. -2t^2+3t+4 C. 4t-7 D. None of The Above Choose all answers that apply
Nikitich [7]

Answer:

B. -2t^2+3t+4

Step-by-step explanation:

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ax^2 + bx + c

Option B meets that requirement, even though it has a '-' in front

5 0
3 years ago
It took Jimena 89 minutes to run a 15-kilometer race last weekend. If you know that 1 kilometer equals 0.621 mile, how many minu
Novosadov [1.4K]
The answer is <span>9.55 minutes
</span>
1. Turn 15 km into miles:
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    15 km = 15 * 0.621 mile = 9.315 miles
So, she ran 9.315 miles for 89 minutes

2. Calculate <span>how many minutes it took Jimena to run 1 mile during the race:
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    She ran 1 mile for x minutes.
    9.315 mi : 89 min = 1 mi : x
    x = 89 min * 1 mi / 9.315 mi
    x = 9.55 min
3 0
3 years ago
Look at photo asap please <br><br><br><br><br><br><br>​
aivan3 [116]

Answer:

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3 0
3 years ago
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
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