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lutik1710 [3]
3 years ago
15

Find a − b when a = −7 and b = 11.

Mathematics
1 answer:
Mariana [72]3 years ago
3 0

Answer:

-18

Explanation:

a - b

a = -7

b = 11

Insert -7 for 'a' and 11 for 'b'

-7 - 11

= -18

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7. If every short side is 1.5 inches and every long side is 3 inches, what is the perimeter?
hjlf
The answer 2 your question is 24in
6 0
3 years ago
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In the coordinate plane, draw quadrilateral ABCD with A(–5, 0), B(2, –6), C(8, 1), and D(1, 7), then demonstrate that ABCD is a
Len [333]

Answer:

ABCD is a rectangle

Step-by-step explanation:

∵ A = (-5 , 0) , B = (2 , -6) , C = (8 , 1) , D = (1 , 7)

∵ The x-coordinate of the mid-point of AC = (-5 + 8)/2 =3/2

∵ The y-coordinate of the mid-point of AC = (0 + 1)/2 = 1/2

∴ The mid-point of AC = (3/2 , 1/2)

∵ The x-coordinate of the mid-point of BD = (2 + 1)/2 =3/2

∵ The y-coordinate of the mid-point of BD = (-6 + 7)/2 = 1/2

∴ The mid-point of BD = (3/2 , 1/2)

∴ The mid-point of AC = The mid-point of BD ⇒ (1)

∵ AC = √[(8 - -5)²+(1 - 0)² = √170

∵ BD = √[(1 - 2)²+(7 - -6)² = √170

∴ AC = BD ⇒ (2)

From (1) and (2)

AC and BD equal each other and bisects each other

∴ ABCD is a rectangle

7 0
3 years ago
In this question, all lengths are in centimetres.
JulsSmile [24]

Answer:

Step-by-step explanation:

AB/AC =1/2

(3x-4)/(2x+12)=1/2

2(3x-4) = 1(2x+12)

6x-8=2x+12

4x=20

X=5

AC/BC =3x-4/7x-2=22/33=2/3

AB/AC=3x-4/7x-2=22/33=2/3

AB/AC=3x-4/2x+12

6x-8=2x+12

You would get 4/5 still trying to work out the last mark

3 0
3 years ago
A plane flies at 350 mph in the direction N 40° E with a wind blowing at 40 mph in the direction S 70° E. What is the plane’s dr
kozerog [31]

Answer:

The drift angle is approximately 7.65° towards the East from the plane's heading

Step-by-step explanation:

The speed of the plane = 350 mph

The direction in which the plane flies N 40° E = 50° counterclockwise from the eastern direction

The speed of the wind = 40 mph

The direction of the wind = S 70° E = 20° clockwise from the eastern direction

The component velocities of the plane are;

R_{Plane} = (350 × cos 50)·i + (350 × sin 50)·j

R_{Wind} = (40 + cos 20)·i - (40 × sin 40)·j

The resultant speed of the plane = R_{Plane} + R_{Wind} = 265.915·i +242.404·j

The direction the plane is heading = tan⁻¹(242.404/265.915) ≈ 42.35°

Therefore, the drift angle = Actual Angle - Direction of the plane = 50 - 42.35 ≈ 7.65° towards the East

7 0
3 years ago
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Can someone answer this and tell me how to solve please?
Julli [10]
It’s a ‘reflection across y=x’ or option 3.
3 0
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