Answer:
A. Yes, the triangles are congruent by SAS.
Step-by-step explanation:
EF = FG and DF = FH-> Given
angle EFD = angle HFG -> Vertical angles are congruent
DE F = HGF -> SAS Triangle Congruence Theorem
Answer: that's false
Step-by-step explanation:
degrees of freedom=(r-1)(c-1)
If I'm wrong I'm sorry
12.18 that is the answer to the question
Step-by-step explanation:
The equation will form a circle because it in the form of

First, let set the equation equal.

Here the center will be (7,-5), and the radius of 5. The boundary line will be dashed
Since this is in the inequalities, we must find the solution set.
Plug in 0,0 for x and y and see if it's true.



This is a true so we shade the region that includes 0,0
Since 0,0 has a greater distance from the center of the circle, 0,0 is outside of the circle, so our solution set will
be outside of circle.
Here a picture of graph,