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4 years ago

Which of the following powers is responsible for establishing the United Nations?

Mathematics

1 answer:

n200080 [17]4 years ago

4 0

Answer:

B Allied Powers

Step-by-step explanation:

They worked with the US during WWI and WWII

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n 1895, the first Putting Green Championship was held. The winner’s prize money was $200. In 2016, the winner’s check was $1,480

Amanda [17]

Answer:

7.64% per year
$10,805,480 . . . . rounded to 7 significant figures

Step-by-step explanation:

Using 2016 as a reference (t=0), the exponential equation for winnings can be written as ...

w(t) = 1480000×(1480000/200)^(t/121)

where 1480000 is the winnings in the reference year, and the ratio 1480000/200 is the ratio of winnings increase over the 121 years from 1895 to 2016.

This can be approximated by ...

w(t) ≈ 1,480,000×1.07640850764^t

In this form, we can see that the annual percentage increase is ...

1.0764 -1 = 7.64%

Then the winner's check in 2043, 27 years after 2016, is predicted to be ...

w(27) = $1,480,000×(1.0764...)^27 ≈ $10,805,478.41 ≈ $10,805,000

8 0

3 years ago

There are 220 people who voted at the 6th grade meeting.Sixty percent of the voters are in favor of changing the school mascot.H

Amiraneli [1.4K]

60% of 220 is 132.
220 -132 = 88

88 people.

4 0

4 years ago

The median of $20, x, 15, 30, 25$ is $0.4$ less than the mean. If $x$ is a whole number, what is the sum of all possible values

34kurt

Answer:

198

Step-by-step explanation:

5 0

3 years ago

Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

2 years ago

What's the value of x <br>-1+6x=-2

ExtremeBDS [4]

-1 + 6x = - 2 |add 1 to both sides

6x = -1 |divide both sides by 6

x = - 1/6

5 0

3 years ago

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