Answer:
Q1
<u>The exponential growth model for frogs:</u>
F- number of frogs, x- number of years, 1.22 - growth factor
<u>Calculations</u>:
- F(5) = 100(1.22)⁵ = 270
- a) F(10) = 100(1.22)¹⁰ = 730
- b) F(20) = 100(1.22)²⁰ = 5335
<em>All numbers rounded </em>
Q2
<u>The exponential growth model for bacteria:</u>
B- number of bacteria, x- number of hours, 1.8 - growth factor
<u>Calculations:</u>
- a) B(5) = 10(1.8)⁵ = 189
- b) B(24) = 10(1.8)²⁴ = 13382588
- c) B(168) = 10(1.8)¹⁶⁸ = 7.68 * 10⁴³
<em>All numbers rounded </em>
Q3.
<u>The exponential growth model for fish:</u>
F- number of fish, x- number of months, 1.02 - growth factor
<u>Calculations:</u>
- a) F(12) = 821(1.02)¹² = 1041
- b) F(120) = 821(1.02)¹²⁰ = 8838
<em>All numbers rounded </em>
The answer to #1 is 9 to 30
the answer to #2 is 4 to 3
Answer:
a) y = -500x + 130,000
b)67,500 gallons remaining
c) 260 hours
Step-by-step explanation:
Since water is being removed at a rate of 500 gallons per hour, the slope would be a negative.
a) y = -500x + 130,000
For<u> part b</u> input 125 for x:
y = -500(125) + 130,000
y = 67,500
There are 67,500 gallons remaining
For part c we are solving for the x intercept
0 = -500x + 130,000
Subtract 130,000 from both sides
-130,000 = -500x
x = 260
It will take 260 hours for the pool to completely drain
Answer: n = 267
Step-by-step explanation: <u>Margin</u> <u>of</u> <u>Error</u> shows the percentage that will differ the result you get from the real population value or, in other words, is the range of values in a confidence interval.
It can be calculated as
margin of error = 
in which
z is z-score related to the confidence interval, which is this case is 1.96;
s is standard deviation;
n is the number in a sample;
So, the number of mice must be:
margin of error =
n = 267
<u>For the margin of error with 95% confidence interval be 0.6, it is needed </u><u>267 mice</u><u>.</u>
Slope=rise/run
rise=-15 feet (since it's downhill)
run=24 feet
slope=-15/24=-5/8
slope=-5/8
