The correct question is
<span>Which equation can you use to solve for x? x + 56 = 180 x + 146 = 180 180−x=146 x + 56 = 146 The figure contains a pair intersecting lines. One of the four angles formed by the intersecting lines is labeled 146 degrees. The angle opposite and not adjacent to this angle is broken into two smaller angles by a ray that extends from the point where the two lines intersect. One of these smaller angles is labeled
56 degrees, and the other smaller angle is labeled
x degrees.see the picture attached to better understand the problem
we know that
angle 146</span>° and angle (56°+x°) area equal -----> by vertical angles
so
146=56+x
therefore
the answer is<span>
x + 56 = 146</span>
3,240 ......................
The only rule to follow is
Divide dividend by divisor and the mention the quotient and things left after remains in place of remainder
Here is a sample

Answer: 0.1
Step-by-step explanation:
Given
Bag-I has 2 blue,3 orange, 5 red
Bag-II has 4 Pink,10 blue, 6 brown
No of ways of choosing a blue marble from bag-I

Total no of ways of choosing a marble from bag-I

No of ways of choosing a blue marble from bag-II

Total no of ways of choosing a marble from bag-II

The probability that he will pull out a blue marble from each bag is

