−3c 4 −5c 2 −7c)+(4c 4 +8c 3 +2c 2 )

Mathematics

1 answer:

ddd [48]3 years ago

7 0

Answer:

Look at the image attached.

Step-by-step explanation:

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Given the four vectors in component form:

Kazeer [188]

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2 years ago

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If a polynomial function f(x) has roots -8, 1, and 6i, what must also be a root of f(x)?

Naddik [55]

Answer:

it must also have the root : - 6i

Step-by-step explanation:

If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.

This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:

$(x-(a+bi))*(x-(a-bi))=\\(x-a-bi)*(x-a+bi)=\\([x-a]-bi)*([x-a]+bi)=\\(x-a)^2-(bi)^2=\\(x-a)^2-b^2(-1)=\\(x-a)^2+b^2$

where the imaginary unit has disappeared, making the expression real.

So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)

Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.

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3 years ago

Can't find the answer for when they arrived at the same time

Alla [95]

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3 years ago

Four resistors are connected in series such that their total resistance is 50ohm . If the resistance of resistors is 5 ohm , 10o

Katyanochek1 [597]

<h2>Answer:</h2>

$\boxed{R_{4}=20\Omega}$

<h2>Step-by-step explanation:</h2>

If resistors are in series, so the current $I$ is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance of series combination and the four resistors as follows: