Addition Property of Equality
A) -3.5*2^2*3=-14*3=-42
c) -3*y*z^2=-3*(-4)*3^2=12*9=108
6x*y^2=6*2*(-4)^2=12*16=192
P=2*(108+192)=2*300=600
b) 5/2*(-4)^2=5/2*16=40
2|x-5|<16 has several integer solutions. What are they?
First, div. both sides by 2, obtaining |x-5| < 8.
One way to solve this would be to add 5 to both sides: |x| < 13.
This inequality has several integer soltuions. One such solution is 12. Notice how |12| < 13 is true. Another solution is -12. Show that this is true.
Then the solution set is {-12, -11, -10, .............. , 11, 12}
I think the answer is 10 because:
6x2=12
12+2x-32=0
make the like terms together = 12-32+2x=0
= -20+2x=0
again make the like terms together = 2x=0+20 [sign changes when it goes to the other side]
so, 2x=20
x=20/2 [ multiplication will change into division when it goes to the other side]
therefore x=10
