1/4=4/16 so the can has 3 servings and a some leftovers that are smaller than a serving. I think the answer is 3.
The slope of the tangent line to
at
is given by the derivative of
at that point:

Factorize the numerator:

We have
approaching -1; in particular, this means
, so that

Then

and the tangent line's equation is

<h3>
Answer: -7 < x < 17</h3>
====================================================
Explanation:
Plug in the lower bound of the domain, which is x = -3
f(x) = 3x+2
f(-3) = 3(-3)+2
f(-3) = -9+2
f(-3) = -7
If x = -3, then the output is y = -7. Since f(x) is an increasing function (due to the positive slope), we know that y = -7 is the lower bound of the range.
If you plugged in x = 5, you should find that f(5) = 17 making this the upper bound of the range.
The range of f(x) is -7 < y < 17
Recall that the domain and range swap places when going from the original function f(x) to the inverse 
This swap happens because how x and y change places when determining the inverse itself. In other words, you go from y = 3x+2 to x = 3y+2. Solving for y gets us y = (x-2)/3 which is the inverse.
-----------------------
In short, we found the range of f(x) is -7 < y < 17.
That means the domain of the inverse is -7 < x < 17 since the domain and range swap roles when going from original to inverse.
Answer:

Step-by-step explanation:
Given



Required
Area of triangle
This is calculated as:

This gives:



--- approximated
13/5 or 2 3/5 by the way nice profile picture