Question

20% of the time Tucker eats out twice a month, 30% of the time he eats out once a month, and 50% of the time he doesn't eat out at all in a given month. What is the expected value for the number of times Tucker eats out during a month?

Answer 1

Answer:

0.7

Step-by-step explanation:

Given that :

20% of the time Tucker eats out twice a month, 30% of the time he eats out once a month, and 50% of the time he doesn't eat out at all in a given month.

THIS CAN be expressed in terms of probability distribution thus :

X : _____ 2 _____ 1 _______0

P(X) : __ 0.2 ____ 0.3 ____ 0.5

Hence, expected value for the number of times Tucker eats out during a month

E(x) = Σ(X)*p(x)

E(x) = (2 * 0.2) + (1 * 0.3) + (0 * 0.5)

E(x) = 0.4 + 0.3 + 0

E(x) = 0.7