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FromTheMoon [43]
3 years ago
5

Find r 25= r•r•8 hurry go fast please

Mathematics
1 answer:
ELEN [110]3 years ago
7 0

Answer:

r = \frac{5}{2\sqrt{2} } \\r = -\frac{5}{2\sqrt{2}}

Step-by-step explanation:

25= r•r•8 ⇔ 25/8 = r²

then

r^{2} =(\frac{5}{2\sqrt{2} } )^{2} \\\\Then\\\\r = \frac{5}{2\sqrt{2} } \\Or\\r = -\frac{5}{2\sqrt{2}}

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The perimeter of a triangle is 12in. After a dilation, the perimeter is now 60in. What is the scale factor?
LenaWriter [7]

Answer:

scale factor = 5

Step-by-step explanation:

60/12 = 5!!

super easy:)

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Who got the answers for lib arts 1 flvs 1.07??
aleksklad [387]

Answer:

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Step-by-step explanation:


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3 years ago
The total employment for police officers in 2006 was 648,000. If there are 719,000 police officers in 2016, what will the percen
Lubov Fominskaja [6]
If you increase the number of police officers from 648,000 to 719,000...you have increased the total employment by 719,000 minus 648,000 
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3 years ago
A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a
tatuchka [14]

Answer:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

df=n-1=15-1=14  

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

\bar X=42.6 represent the average nicotine content

s=3.7 represent the sample standard deviation

n=15 sample size  

\mu_o =40 represent the value to check

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:  

Null hypothesis:\mu \leq 40  

Alternative hypothesis:\mu > 40  

The statistic for this case would be:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

And replcing we got:

t=\frac{42.6-40}{\frac{3.7}{\sqrt{15}}}=2.722    

The degrees of freedom are:

df=n-1=15-1=14  

The p value would be:

p_v =P(t_{(14)}>2.722)=0.0083  

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

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3 years ago
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stellarik [79]

Answer:

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Step-by-step explanation:

Ok so we know that numbers that end with 1,3,5,7 and 9 are odd numbers and all the numbers listed in the question all end with these numbers.

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