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2 years ago

Identify the center and radius of the circle with equation. ( please help me )

Mathematics

1 answer:

lutik1710 [3]2 years ago

6 0

Answer:

Center = (4, -5)

radius = 6

======================================================

Explanation:

The general template of any circle is

(x-h)^2 + (y-k)^2 = r^2

Rewrite the given equation into this form

(x-4)^2 + (y- (-5))^2 = 6^2

We can see that (h,k) = (4,-5) is the center and r = 6 is the radius.

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Help plz I need to fin before today help

Alik [6]

Answer:

BD = 12.1 (nearest tenth)

Step-by-step explanation:

∆ABC is an isosceles triangle, since it has two equal sides, AB and BC. Also, this means that <BAD and <BCD = 60° each.

BD divides ∆ABC into two equal parts.

Apply trigonometric ratio to find BD.

Reference angle = <BAD = 60°

Adjacent = AD = 7

Opposite = BD

Thus, we would have:

tan 60 = opp/adj

Tan 60 = BD/7

7*Tan 60 = BD

12.1 = BD

BD = 12.1 (nearest tenth)

8 0

2 years ago

24 cooking takes for 384 sprinkles, how many sprinkles would 60 cookies need

alukav5142 [94]

Answer:

960 i think

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po

emmasim [6.3K]

$\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS$
$\displaystyle\iint_\sigma\mathbf F\cdot\mathbf n\,\mathrm dS$
$\displaystyle\iint_\sigma\mathbf F\cdot\left(\frac{\mathbf r_u\times\mathbf r_v}{\|\mathbf r_u\times\mathbf r_v\|}\right)\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dA$
$\displaystyle\iint_\sigma\mathbf F\cdot(\mathbf r_u\times\mathbf r_v)\,\mathrm dA$

Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

$\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k$
$\mathbf r_v=\dfrac\partial{\partial v}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=-2\sin v\,\mathbf i+\cos v\,\mathbf j$

The cross product is

$\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j$

So, the flux is given by

$\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA$
$\displaystyle\int_0^5\int_0^{2\pi}(-e^{-\sin v}\cos v+2\sin^2v)\,\mathrm dv\,\mathrm du$
$\displaystyle-5\int_0^{2\pi}e^{-\sin v}\cos v\,\mathrm dv+10\int_0^{2\pi}\sin^2v\,\mathrm dv$
$\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv$

where $t=-\sin v$ in the first integral, and the half-angle identity is used in the second. The first integral vanishes, leaving you with

$\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi$

5 0

2 years ago

What is completely factored form of d^4-81

romanna [79]

Answer:

(d − 3) (d + 3) (d² + 9)

Step-by-step explanation:

d⁴ − 81

Factor using difference of squares.

(d² − 9) (d² + 9)

Factor using difference of squares again.

(d − 3) (d + 3) (d² + 9)

5 0

2 years ago

Audra and Darcy both play softball. Audra started the season with 5 home runs and is

Arte-miy333 [17]

Answer:

No Solutions

Step-by-step explanation:

We have to create an equation to be able to solve this problem.

Let's let x = the # of home runs

The equation that helps us solve this is 5 + 1x = 10 + 1x

First, we have to subtract 1x from each side (always subtract the variable first before the constant, math rule)

This brings us to 5=10 because the x's cancel each other out.

You probably look at this saying, wait, this isn't right, and you would be correct

Since this equation isn't true, it is No Solutions

No Solutions mean there is no answer to the problem, it is impossible to solve.

So, our final answer is No Solutions

Hope this helps, have a great day! :)

4 0

1 year ago