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Novay_Z [31]
3 years ago
8

Suppose an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline that

will have the best fuel economy. The four grades are regular, economy, premium, and super premium. The test car made three trial runs on the test track using each of the four grades. The miles per gallon were recorded for each grade. At the 0.05 level, what is the critical value of F used to test the hypothesis that the miles per gallon for each fuel are the same?
Mathematics
1 answer:
Deffense [45]3 years ago
8 0

Answer:

The F-statistic used to test the hypothesis that the miles per gallon for each fuel are the same is 4.07.

Step-by-step explanation:

There are four treatments in the data given, i.e. k = 4.

Total number of observations, n = 12.

Note: degrees of freedom is denoted as df.

For treatment, the degrees of freedom = k-1 = 4-1 =3 df.

The total degrees of freedom = n-1 = 12-1 = 11 df.

The error in degrees of freedom = df (total) - df(treatment)

The error in degrees of freedom = 11 - 3 = 8 df

At α = 0.05 level,from the F table, the F-statistic with (3 , 8)df is 4.07.

Therefore, the F-statistic used to test the hypothesis that the miles per gallon for each fuel are the same is 4.07.

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topjm [15]

fans bought 5/8 so there is 3/8 still left

45000 * 3/8 = 16,875 seats are left

7 0
3 years ago
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How many five-card hands (drawn from a standard deck) contain exactly three fives? (A five-card hand is any set of five differen
VashaNatasha [74]

Answer:

4512.

Step-by-step explanation:

We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.

The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4

48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128

We can choose exactly three fives from five-card hands in 4C3*48C3 ways.

4C3*48C3=4*1128=4512

Therefore, 4512 five card hands contain exactly three fives.

4 0
3 years ago
You and your friend were taking turns rolling a die when you thought of a game: If a one is rolled by either player, you pay you
Mazyrski [523]

Answer:

6 times

Step-by-step explanation:

1. There was no cents left

2. If you roll one and get 50 cents you have to minus it with rolling other number than 'one' 5 times because you'll get 10 minus if you roll another number (50 divided by 10 is 5)

3. If you divid 30 (The rolls) by 5 (amount of roll you have to roll if you get one)

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6 0
3 years ago
Please solve with work much appreciated
mamaluj [8]

Answer:

0.046  

Step-by-step explanation:

\text{BAC} = \dfrac{10N - 7.5H}{6.8 M}

Data:

N = 4

H = 2

M = 80

Calculation:

\text{BAC} = \dfrac{10N - 7.5H}{6.8M} = \dfrac{10\times4 - 7.5\times2}{6.8\times80} = \dfrac{40 - 15}{544} = \dfrac{25}{544} = 0.046

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3 years ago
I need the answers fast
anygoal [31]

Answer:

w=51

x=90

y=38

Step-by-step explanation:

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5 0
3 years ago
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