Required area of shaded portion
= Area of square ABCD - 4 × area of one quadrant
![= 14 \times 14 - 4 \times \frac{90}{360} \times \frac{22}{7} \times (7) \times (7)](https://tex.z-dn.net/?f=%20%3D%2014%20%5Ctimes%2014%20-%204%20%5Ctimes%20%5Cfrac%7B90%7D%7B360%7D%20%5Ctimes%20%5Cfrac%7B22%7D%7B7%7D%20%5Ctimes%20%287%29%20%5Ctimes%20%287%29)
Answer:
≥ and ≤ will both be solid dots, as it includes the number
x ≥ -7 is everything greater than -7; x ≤ 4 is everything less than 4.
to include both, you'd click -7, drag right, and stop at 4
Answer: w=5 , L= 2+2(5)=12
Step-by-step explanation:
L=2+2W
A= 60
LxW=60, now we will replace the L
(2+2W)(W)=60 we multiply
2w^2+2w=60
2w^2+2w-60=0 we divide by 2 the equation so we can work easier
w^2+w-30=0
find out w using the quadratic equation
we will get 2 solution,
w=5 and another solution is -6, which is not valid, as the side can not be negative
-3+3x=-2(x+1)
First: I will get rid of the bracket:
-3+3x=-2x-2
Now, all the x goes to the left side, all the numbers without x to the right side:
3x+2x=-2+3
we add up"
5x=1
divide by 5: