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VARVARA [1.3K]
2 years ago
8

. Benson had -$12 in his bank

Mathematics
2 answers:
Maurinko [17]2 years ago
5 0

Answer:

24

Step-by-step explanation:

add 12 ND 39 ND you get 51 then subtract 51 from 75 and get 24

natka813 [3]2 years ago
3 0

Answer: 24

Step-by-step explanation:

you add 12 to 39 which equals 51 then you subtract 51 from 75 which equals 24

hope this helps

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Two of them are drawn simultaneously from a deck of 48 cards.
Elina [12.6K]

The required probability is
a) both are cups is 0.05

b) At least one cup is 0.19

c) One is a cup and the other is a sword is   0.06

<h3 /><h3>What is probability?</h3>

Probability can be defined as the ratio of favorable outcomes to the total number of events.

a) for both are cups

P= 12*11/48*47
p = 0.05

b) for  At least one cup
p = 12*36/48*47
p = 0.19

c) for One is a cup and the other is a sword
p = 12*12/48*47
p = 0.06

Thus, the required probability is 0.05, 0.19, 0.06

Learn more about probability here:

brainly.com/question/14290572

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6 0
2 years ago
Which function is best represented by this graph?
12345 [234]
I believe the answer is C
4 0
3 years ago
Read 2 more answers
4 more than one third of a number n is 6. An equation is? The solution is n =?
harkovskaia [24]

Answer:

 \frac{1}{3}n  + 4  = 6  

6

Step-by-step explanation:

Given problem:

      4 more than one third of a number n is 6

Unknown:

The equation = ?

Solution of the number  = ?

Solution:

 let the number  = n

So, 4 more than one third of a number;

  One third of n = \frac{1}{3}n

  4 more;

                \frac{1}{3}n  + 4

   is 6;

             \frac{1}{3}n  + 4  = 6   (equation of the expression)

Let us now solve the equation:

                         \frac{1}{3}n  + 4  = 6  

                    \frac{1}{3}n = 6 - 4

                   \frac{1}{3}n = 2

                     n = 6

5 0
3 years ago
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The answer would be 2 because the problem(after rewriting it) is -8w+48=32. so then you subtract 48 from both sides and get -8w=-16. then divide both sides by -8 and you get 2
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