Select the most specific name for the quadrilateral shown.

myrzilka [38]

19 x 4 is the equation and the answers is 76

8 0

3 years ago

Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b

kramer

Answer:

(a)

$\bar x = 0.0075$

$s = 0.0049$

(b)

B. The sample is too small to make judgments about skewness or symmetry.

Step-by-step explanation:

Given:

$n = 8$

$\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 \ \end{array}$

Solving (a):

First, calculate the difference between the recorded TBBMC for both operators:

$\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 &{|1 - 2|} &0.003 & 0.015 & 0.006 & 0.004 & 0.002 & 0.010 & 0.005 & 0.015 \ \end{array}$

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.

The mean is then calculated as:

$\bar x = \frac{\sum x}{n}$

$\bar x = \frac{0.003 + 0.015 + 0.006 + 0.004 + 0.002 + 0.010 + 0.005 + 0.015}{8}$

$\bar x = \frac{0.06}{8}$

$\bar x = 0.0075$

Next, calculate the standard deviation (s).

This is calculated using:

$s = \sqrt{\frac{\sum (x - \bar x)^2}{n}}$

So, we have

$s = \sqrt\frac{(0.003 - 0.0075)^2 + (0.015 - 0.0075)^2+ (0.006- 0.0075)^2+ ....... + (0.005- 0.0075)^2+ (0.015- 0.0075)^2 }{8}$ $s = \sqrt\frac{0.00019}{8}$

$s = \sqrt{0.00002375$

$s = 0.0049$

Solving (b):

Of the given options (A - E), option B is correct because the sample is actually too small

6 0

2 years ago

Which will help you build a good credit history

tresset_1 [31]

Make 100% of your payments on time and keep your credit card debt low.

5 0

2 years ago

The maximum afternoon temperature in Granderson is modeled by t=60-30 cos (x<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="T

kicyunya [14]

The equation is $t=60-30 cos (x \frac{\pi}{6})$

the -30 expression, is subtracting, if negative, from the 60
if the cosine returned is negative, you'd end up with a +30,
negative * negative = positive

and then the 30 expression will ADD to the 60 amount
so the temperature "t" is highest, when the 30 expression, is
positive and and it's highest

when does that happen, when cosine is negative and at its highest,
well, cosine range is $-1\le cos(\theta ) \le 1$
so the lowest value cosine can provide is -1, when is cosine -1?
well, at $\pi$

so... let's find a value that makes that expression to $cos(\pi)$

$\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=6
\\\\
thus
\\\\
t=60-30 cos (6 \frac{\pi}{6})\implies t=60-30 cos (\pi )
\\\\
t=60-30[-1]\implies t=60+30\implies t=90$

----------------------------------------------------------------------------------------
so...for August, that'll mean

$\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=7
\\\\
t=60-30 cos (\frac{7\pi}{6})\implies t=60-30\left( -\cfrac{\sqrt{3}}{2} \right)
\\\\
t=60+(15\cdot \sqrt{3})\implies t\approx85.98^o$

4 0

3 years ago

What is the area of this figure?<br>Enter your answer in the box.<br>8m<br>5 m<br>9m

Iteru [2.4K]

Answer:

314 feet

Step-by-step explanation:

6 0

3 years ago

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