Answer:
B
Step-by-step explanation:
y³=64
![y=(64)^{\frac{1}{3} } =\sqrt[3]{64}](https://tex.z-dn.net/?f=y%3D%2864%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B64%7D%20)
To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square.
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial.
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2.
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial.
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1.
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
Answer:
B
Step-by-step explanation:
32x + 24 = 20
24 - 24= 0
20 - 24= -4
32x = -4
32x/32
x
-4/32= -8
X= -1/8
