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krek1111 [17]
3 years ago
15

Marcy left for school and felt like running. She ran for a while and then stopped to rest. After resting, she walked the rest of

the way to school. Click through and select the graph that best represents the story.

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:

The last graph best represents the story

Step-by-step explanation:

Mary left for school from rest. So the initial speed is zero.

So we start from the origin and draw a straight line with a positive slope to running, that is as time increases , distance covered also increases.

When she is resting, her speed is zero so we draw a horizontal line to indicate this second phase of her journey.

After resting she still continued her journey to school.

This part also has a positive slope.

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A production facility employs 10 workers on the day shift, 8 workers on the swing shift, and 6 workers on the graveyard shift. A
PilotLPTM [1.2K]

Answer:

252 ; 0.0059 ; 0.0074 ; 0.9926

Step-by-step explanation:

Day shift = 10

Swing shift = 8

Graveyard shift = 6

Total number of workers = 24

A.) Number of selections resulting in 5 workers coming from day shift :

10C5 = 10! ÷ (10-5)!5!

= (10*9*8*7*6) / (5*4*3*2*1)

= 252

B.) All 5 workers coming from day shift :

Required outcome = 10C5

Total possible outcomes = 24C5

10C5 ÷ 24C5

252 ÷ 42504

= 0.0059288

= 0.0059

C.) 5 selected workers are from the same shift :

[day shift + swing shift + graveyard shift] / total possible outcomes

[(10C5) + (8C5) + (6C5)] ÷ 24C5

(252 + 56 + 6) / 42504

= 0.0074

D.) What is the probability that at least two different shifts will be represented among the selected workers?

1 - [[(10C5) + (8C5) + (6C5)] ÷ 24C5]

1 - 0.0073875

= 0.9926124

= 0.9926

6 0
3 years ago
If 40% is equal to the fraction x/30, what is the value of X?
brilliants [131]
The correct answer is D.12
3 0
3 years ago
Read 2 more answers
ASAP PLEASE
madam [21]

Answer:

he has to pick the phone up 100 more times

6 0
3 years ago
Read 2 more answers
Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
charle [14.2K]

Answer: t = - 5 ∈ I_{1} = ( -∞ , -4 )

Step-by-step explanation:

The standard form of O.D.E is written as :

y^{1} + p(t) = g(t)

Equation given :

(16-t^{2} )y^{1} + 9ty = 5t^{2} ,       y(-5) = 1

The first thing to do is to write the O.D.E in standard form , that is we will divide through by 16 - t^{2} , so we have

y^{1} + \frac{9ty}{16-t^{2}}=\frac{5t^{2}}{16-t^{2}}

With this , we can see that p(t) and g(t) are both continuous in the same domain. Therefore , the intervals are :

I_{1} = ( -∞ , -4 )

I_{2} = ( - 4 , 4 )

I_{3} = ( 4 , -∞ )

recall that y(−5) = 1 , then t = -5

This means that :

t = - 5 ∈ I_{1} = ( -∞ , -4 )

3 0
3 years ago
−5(1−5k)−4(2k+5) pleas
Kazeer [188]

Answer:

<h2>33k - 25</h2>

Step-by-step explanation:

-5(1 - 5k) - 4(2k + 5)      <em>use distributive property a(b + c) = ab + ac</em>

= (-5)(1) + (-5)(-5k) + (-4)(2k) + (-4)(5)

= -5 + 25k - 8k - 20           <em>combine like terms</em>

= (25k - 8k) + (-5 - 20)

= 33k - 25

5 0
4 years ago
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