Answer:
252 ; 0.0059 ; 0.0074 ; 0.9926
Step-by-step explanation:
Day shift = 10
Swing shift = 8
Graveyard shift = 6
Total number of workers = 24
A.) Number of selections resulting in 5 workers coming from day shift :
10C5 = 10! ÷ (10-5)!5!
= (10*9*8*7*6) / (5*4*3*2*1)
= 252
B.) All 5 workers coming from day shift :
Required outcome = 10C5
Total possible outcomes = 24C5
10C5 ÷ 24C5
252 ÷ 42504
= 0.0059288
= 0.0059
C.) 5 selected workers are from the same shift :
[day shift + swing shift + graveyard shift] / total possible outcomes
[(10C5) + (8C5) + (6C5)] ÷ 24C5
(252 + 56 + 6) / 42504
= 0.0074
D.) What is the probability that at least two different shifts will be represented among the selected workers?
1 - [[(10C5) + (8C5) + (6C5)] ÷ 24C5]
1 - 0.0073875
= 0.9926124
= 0.9926
The correct answer is D.12
Answer:
he has to pick the phone up 100 more times
Answer: t = - 5 ∈
= ( -∞ , -4 )
Step-by-step explanation:
The standard form of O.D.E is written as :
+ 
Equation given :
+
=
, 
The first thing to do is to write the O.D.E in standard form , that is we will divide through by
, so we have

With this , we can see that
and
are both continuous in the same domain. Therefore , the intervals are :
= ( -∞ , -4 )
= ( - 4 , 4 )
= ( 4 , -∞ )
recall that y(−5) = 1 , then t = -5
This means that :
t = - 5 ∈
= ( -∞ , -4 )
Answer:
<h2>33k - 25</h2>
Step-by-step explanation:
-5(1 - 5k) - 4(2k + 5) <em>use distributive property a(b + c) = ab + ac</em>
= (-5)(1) + (-5)(-5k) + (-4)(2k) + (-4)(5)
= -5 + 25k - 8k - 20 <em>combine like terms</em>
= (25k - 8k) + (-5 - 20)
= 33k - 25