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Arturiano [62]
3 years ago
13

Ryan uses a random name generator to choose 50 students from his high school. Of

Mathematics
1 answer:
Alika [10]3 years ago
7 0
I predict that 306 of the 850 will where glasses
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Changing the mean and standard deviation of a Normal distribution by a moderate amount can greatly change the percent of observa
sweet-ann [11.9K]

Answer:

a) P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z1.798)

P(Z>1.798)=1-P(z

f. 3.59 %

b) P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z2.21)

P(Z>2.21)=1-P(Z

d. 1.36 %

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores of men of a population, and for this case we know the distribution for X is given by:

X \sim N(527,124)  

Where \mu=65.5 and \sigma=2.6

We are interested on this probability

P(X>750)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z1.798)

And we can find this probability using the complement rule and with the normal standard distribution table or excel:

P(Z>1.798)=1-P(Z

So then the correct answer for this case would be:

f. 3.59 %

Part b

Let X the random variable that represent the scores of women's of a population, and for this case we know the distribution for X is given by:

X \sim N(496,115)  

Where \mu=496 and \sigma=115

We are interested on this probability

P(X>750)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>750)=P(\frac{X-\mu}{\sigma}>\frac{750-\mu}{\sigma})=P(Z2.21)

And we can find this probability using the complement rule and with the normal standard distribution table or excel:

P(Z>2.21)=1-P(Z

So then the correct answer for this case would be:

d. 1.36 %

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3 years ago
The GCF of a number and 96 is 32. The sum of the number's digits is 13. Which choice satisfies these conditions?
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The number 256 satisfiest those conditions

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How do create a box plot
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At the local fast food restaurant, the number of fries sold in one day was six less than three times the number of burgers. If t
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X = burger number. 3x-6 = fries sold
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