Ask question

Ask question

All categories

3 years ago

8

A state of $490,000 is left to three siblings the eldest receives three times as much as the youngest the middle sibling receive

s $15,000 more than the youngest how much did each receive

1 answer:

Elis [28]3 years ago

7 0

Answer:

Step-by-step explanation:

Given

State worth is $\$4,90,000$

Assume the youngest receives x

So, Eldest receives three times of youngest=3x

Middle receives $\$15,000$ more than the youngest=x+15000

Sum of their shares $= 3x+x+15000+x=4,90,000$

$\Rightarrow \quad 5x+15000=4,90,000\\\Rightarrow \quad 5x=4,75,000\\\Rightarrow \quad x=\$ 95,000$

Eldest receives $2,85,000

Middle receives $1,10,000

Youngest receives $90,000

You might be interested in

How can you represent the solutions of an inequality

natka813 [3]

A closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution.

3 0

3 years ago

Read 2 more answers

A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we

kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

$X_{ij}$ = The number which comes up on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

$E(X_{ij})$ = $\frac {1 + 2 + 3 + 4 + 5 + 6}{6}$

= 3.5 ∀ i = 1(1)10 and j = 1(1)20

and,

$E(X^{2}_{ij}$ = $\frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}$

= $\frac {1 + 4 + 9 + 16 + 25 + 36}{6}$

= $\frac {91}{6}$

$\simeq$ 15.166667

so, $Var(X_{ij}$ = $(E(X^{2}_{ij} - {(E(X_{ij})}^{2})$

$\simeq 15.166667 - 3.5^{2}$

= 2.91667

and $\sigma_{X_{ij}}$ = $\sqrt {2.91667}[/tex [tex]\simeq 1.7078261036$

Now we get that,

$Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}$

We get that $Y_{j}'s$ are iid RV's ∀ j = 1(1)20

Let, ${\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}$

So, we get that $E({\overline}{Y}) = E(Y_{j})$

= $E(X_{ij}$ for any i = 1(1)10

= 3.5

and,

$\sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}} = \frac {\sigma_{X_{ij}}}{\sqrt {20}} = \frac {1.7078261036}{\sqrt {20}} [tex]\simeq 0.38$

Hence, the option which best describes the distribution being simulated is given by,

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

6 0

3 years ago

WHO EVER GETS IT RIGHT GET BRAINLEST

iragen [17]

Answer:

<em>(-25)</em>

Step-by-step explanation:

-43-(-18)

When u multiply minus into minus answer will be plus

-43+18

<em>(-25)</em>

<em>Hope you got it</em>

<em> If you have any question just ask me </em>

<em>If you think this is the best answer please mark me as brainliest</em>

<em />

6 0

3 years ago

Read 2 more answers

Without using a calculator, determine the number of real zeros of the function

natta225 [31]

There should be a total of 3 zeros because the largest exponent is 3.

8 0

3 years ago

PLZZZZ HELP MEEEEE IM GIVING 20 POINTS

Naily [24]

1.theoretical is not counting the results of the experimentssince there are an equal number of red and black and red, the probblity (theoretical) of picking a black one is 1/3
experimental=number of outcomes happened/total number of tests4 times black, 4 tests, so 4/4 or 100%=experimental proablity

2. experimental considered previous trials and theoretical did not

3. theoretical=(1/4) the trials don't influence each other so1/(4*4)=1/16

3 0

2 years ago