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Yuki888 [10]
3 years ago
7

F f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?

Mathematics
1 answer:
Likurg_2 [28]3 years ago
6 0

Answer:

Step-by-step explanation:

f(1) = 160

f(n + 1) = -2 * f(n)

n = 1

f(2) = -2*f(1)

f(2) = -2*160

f(2) = - 320

f(3) = - 2*f(2)

f(3) = -2 * - 320

f(3) = 640

f(4) = -2 * f(3)

f(4) = -2 * 640

f(4) = - 1280

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A segment is created from points A and B. To copy segment AB, which of the following needs to be identified for the construction
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Answer:

(D)The distance between points A and B

Step-by-step explanation:

To copy a segment AB, the first thing is to identify the length of the segment which is the distance between points A and B. It is this distance that will be used to create a new segment at a given point not on the segment.

Midpoints have nothing to do with copying a segment.

<u>The correct option is D.</u>

4 0
3 years ago
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Vlada [557]
X=18
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3 years ago
Use slopes to determine if the lines y= -x/3- 9 and 6x – 2y = -5 are perpendicular.
WARRIOR [948]

Answer:

They are perpendicular.

Step-by-step explanation:

When we convert the equation 6x-2y=-5 into y=mx+b form, it changes into y=3x-5/2. Since we know that perpendicular slopes are opposite reciprocal, the opposite reciprocal of -x/3 is 3. So, we know that these 2 slopes are perpendicular.

8 0
4 years ago
The amount of time required to download a song from Michael's computer to his music player is the same for each song he download
Evgesh-ka [11]

Answer:

The correct answer is A. 1.6

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3 0
3 years ago
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A lead ball weighs 326 grams. Find the radius of the ball to the nearest tenth of a<br> centimeter.
rjkz [21]

Answer:

1.9cm

Step-by-step explanation:

The density d of a material is related to its mass m and volume V as follows;

d = \frac{m}{V}             ------------------(i)

The material in question here is the lead ball.

Now, from known experiment;

the density of lead is <em>11.34g/cm³</em>

From the question, the weight/mass of the lead ball is <em>326g</em>

Substitute these values into equation (i) as follows;

11.34 = \frac{326}{V}

V = \frac{326}{11.34}

V = 28.75cm³

Now, since the ball is of course spherical, we can get the radius by using the following relation from the volume of a sphere;

V = \frac{4}{3} \pi r^3          [V = volume, r = radius]

V = 28.75cm³

=> 28.75 = \frac{4}{3} \pi r^3

=> 3 x 28.75 = 4 π r³

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=> 21.5625 = (3.142) r³      [divide both sides by 3.142]

=> 6.86 = r³              [Take the cube root of both sides]

=> ∛6.86 = ∛r³

=> 1.90 = r

Therefore, the radius is 1.9cm to the nearest tenth

5 0
3 years ago
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