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Delicious77 [7]
3 years ago
7

amelia spent $5.25 for a drink and a sandwich or drink cost $1.35 did she have a turkey sandwhich for $4.22 a tuna sandwich for

$3.92 or ham sandwich for $3.46 use the equation S +1.35=5.27 to justify your answer
Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Answer:

$3.46 or $3.92

Step-by-step explanation:

it has to be $3.46 because you have to remember that tax is included and it could cost more than what you are paying for the sandwich or drink. but the other possible answer is $3.92 if you're not paying any tax.

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It’s on solving systems of equations... can anyone help me pls
dalvyx [7]
The answer for this is (2,3)
8 0
3 years ago
A large bag or sugar weighs 7 1/2 lb. Gow Much does 1 1/4 bags of sugar weighs
arsen [322]

Answer:

The correct option is 4.

Step-by-step explanation:

It is given that the weight of a large bag of sugar is 7\frac{1}{2}. This complex fraction can be written as

7\frac{1}{2}=\frac{14+1}{2}=\frac{15}{2}

So, the weight of a large bag of sugar is \frac{15}{2}.

The number of bags is 1\frac{1}{4}. It means the number of bags is number of bags is \frac{5}{4}.

1\text{ Bag}=\frac{15}{2}\text{ lb}

Multiply both side by \frac{5}{4}.

1\times \frac{5}{4}\text{ Bag}=\frac{15}{2}\times \frac{5}{4}\text{ lb}

\frac{5}{4}\text{ Bag}=\frac{75}{8}\text{ lb}

\frac{5}{4}\text{ Bag}=9\frac{3}{8}\text{ lb}

Therefore correct option is 4.

5 0
3 years ago
Read 2 more answers
Help<br> _<br> _<br> _<br> _<br> __<br><br> _<br><br><br> __<br><br> -bv
lorasvet [3.4K]
ANSWER:
7 x 6 - 4

Hope it helps u!
7 0
3 years ago
Read 2 more answers
The data given to the right includes data from ​candies, and of them are red. The company that makes the candy claims that ​% of
Dafna1 [17]

Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

n = 39, \pi = \frac{8}{39} = 0.2051

Hence the bounds of the interval are:

  • \pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 - 1.96\sqrt{\frac{0.2051(0.7949)}{39}} = 0.0784
  • \pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2051 + 1.96\sqrt{\frac{0.2051(0.7949)}{39}} = 0.3318

As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

7 0
2 years ago
If jimmy had had 9 apples and karl has 10 how mush togheter
sveticcg [70]
19? Lol........................
7 0
3 years ago
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