All categories

3 years ago

A 16-ounce bottle of shampoo costs $4.69. What is the price per ounce, rounded to the nearest cent?

Mathematics

2 answers:

tigry1 [53]3 years ago

6 0

its $3.41 (d) because if you around 4 it will be 3 (im rlly bad at explaing stuff im sorry >-<)

Leto [7]3 years ago

5 0

What is the price per ounce, rounded to the nearest cent? $0.29.

You might be interested in

Solve for y.<br><br> 8(y – 2) = 4y

Arte-miy333 [17]

Answer:

y =4

Step-by-step explanation:

8(y – 2) = 4y

Distribute

8y -16 =4y

Subtract 8y from each side

8y-8y -16 = 4y -8y

-16 = -4y

Divide each side by -4

-16/-4 = -4y/-4

4 = y

7 0

2 years ago

You and three friends are making a gift basket. You want to keep the cost below $12 per person. Write and solve an inequality th

Aneli [31]

Ur answer is letter a <span />

7 0

2 years ago

Step by step explanation please so I can see how to do it

Basile [38]

Answer:

875 units

Step-by-step explanation:

35/5=7 AD and BC =7

25/5=5 the ratio of the to rect are 5

7(5)=35 EH and FG =35

25(35)=875

can you mark me the brainliest please

3 0

2 years ago

Over which interval is the graph of the parent absolute value function f(x) = |xl decreasing?

Romashka [77]

Answer:

(-∞,0)

Step-by-step explanation:

Graph y=|x|

Note that the graph is shaped like a V. The left half of the graph is decreasing from -∞ up until 0 when it hits the origin and starts to increase. Put this into interval notation: (-∞,0).

8 0

3 years ago

Read 2 more answers

I need help finding the area

aniked [119]

<h3>Given :</h3>

Base of triangle = 7 yd
Height of triangle = 10 yd

$\\ \\$

Area of triangle

$\\ \\$

We know:-

When base and height of triangle is given we use this formula:

$\bigstar \boxed{ \rm Area \: of \: triangle = \frac{base \times height}{2} }$

$\\ \\$

So:-

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{base \times height}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 10}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times2 }{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times\cancel2 }{\cancel2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times1 }{1} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5$

$\\ \\$

$\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2} \\$

$\\ \\$

$\therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^{ \red2} }}$

$\\ \\$

$\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}$ ]

7 0

1 year ago