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4 years ago

What is 4 1/3 - 1 5/9

Mathematics

2 answers:

Semenov [28]4 years ago

6 0

Hoping this is what you are looking for. ...

morpeh [17]4 years ago

3 0

<span> 4 1/3 - 1 5/9
</span>= 4 3/9 - 1 5/9
= 3 12/9 - 1 5/9
= 2 7/9

hope it helps

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Which number line best shows the position of square root of 13?

BaLLatris [955]

I assume you mean one that is not rational, such as √2. In such a case, you make a reasonable estimate of it's position, and then label the point that you plot.
For example, you know that √2 is greater than 1 and less than 2, so put the point at about 1½ (actual value is about 1.4142).
For √3, you know the answer is still less than 4, but greater than √2. If both of those points are required to be plotted just make sure you put it in proper relation, otherwise about 1¾ is plenty good (actual value is about 1.7321).
If you are going to get into larger numbers, it's not a bad idea to just learn a few roots. Certainly 2, 3, and 5 (2.2361) and 10 (3.1623) shouldn't be too hard.
Then for a number like 20, which you can quickly workout is √4•√5 or 2√5, you could easily guess about 4½ (4.4721).
They're usually not really interested in your graphing skills on this sort of exercise. They just want you to demonstrate that you have a grasp of the magnitude of irrational numbers.

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3 years ago

What is y = -2x - 9 I am confused

gizmo_the_mogwai [7]

Answer:

its a line on the graph. point at (0,-9) and you move down 2 and 1 to the right and repeat To continue the line start at (0,-9) again and move up to and 1 to the left and repeat. Did that answer your question?

Step-by-step explanation:

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3 years ago

Read 2 more answers

If f(x) = -6x + 6, then f-(x) =D

Basile [38]

Answer: f-(x)=6x-6

Step-by-step explanation: Negative times a positive is negative. Negative times a negative is a positive. Works the same with f(x) representation.

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3 years ago

You are checking the intermediate results of a phone app that calculates the weight of an object in kilograms given the weight i

Ganezh [65]

Answer:

Step 4, because there is only 1 conversion needed.

Step-by-step explanation:

To convert pounds to kilograms, one only needs to divide by (2.2 pounds/kg). That was done in Step 3, so no further steps are needed.

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4 years ago

What is the ratio of the area of the inner square to the area of the outer square?

Setler [38]

Answer:

Step-by-step explanation:

If we are looking for the ratio of the area of the inner square to the area of the outer square, that means that we need the areas of each of these squares, and we need to find the areas without any numbers. But that's ok; the answer they want is not a number answer. The answer will have a's and b's in it instead of numbers.

First the area of the inner square. Here we go:

Look at the triangle in the lower left corner of this coordinate plane. It is a right triangle. The height of it is b. That's because the height is a "y" thing and the y-coordinates of each of those sets of coordinates is b and 0. The height is then b - 0 = b.

The length of the base is a - b. That's because the length is an "x" thing and the x-coordinates of each of those sets of coordinates is (a - b) and 0. The length is then a - b - 0 = a - b.

Now we need the length of the hypotenuse which also serves as one of the sides of the inner square. Using Pythagorean's Theorem, we can find the length of the hypotenuse, which I will label as "?":

$?^2=b^2+(a-b)^2$ and

$?^2=b^2+a^2-2ab+b^2$ and

$?^2=a^2-2ab+2b^2$ so

?, the length of the hypotenuse, is

$?=\sqrt{a^2-2ab+2b^2}$ and now we can use that to find the area of the inner square. The formula for a square's area is

$A=s^2$ so

$A=(\sqrt{a^_2}-2ab+2b^2})^2$ which gives us finally:

$A=a^2-2ab+2b^2$ **

Now for the outer square. Those blue triangles you see are all congruent. We can use the side lengths for the triangles we found above to find the length of a side of the outer square. One side of the outer square is made up of one base length of these triangles and one height. We found the base length to be (a - b) and the height to be b; therefore, the length of one side of the outer square is b + (a - b) which is just "a". That's is, just a length of "a". The area is found by multiplying this side length by itself, so the area of the outer square is

A = a²

The ratio of the area of the inner to the outer is:

$\frac{A_i}{A_o}:\frac{a^2-2ab+2b^2}{a^2}$ and that does not reduce.

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3 years ago