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NNADVOKAT [17]
2 years ago
6

the mean of 200 item was 50 later on it was found that two items were wrongly taken as 92 and 8 instead of 192 and 88 find the c

orrect mean.​
Mathematics
2 answers:
FinnZ [79.3K]2 years ago
7 0

Answer:

Since, mean of 200 items was 50 and number of items =200

So, mean =50

Also, we know mean = number of itemssum of items

∴50=200sum of items

Sum of items = 200×50=10000

Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88 respectively

Then  misread         instead         Correct item

             92                   192              192-92=100

              8                     88               88-8=80

∴ Correct sum of items =10000+180=10180

∴ Correct mean = number of items/sum of items

=10180/200 =50.9

lorasvet [3.4K]2 years ago
6 0

Answer:

Hello,

203.6

Step-by-step explanation:

Sum of the item first= 50*200=10000

new sum is 10000+(192-92)+(88-8)=10180

New mean=10180/200=50.9

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3 years ago
If x2 = 40, what is the value of x?
Alina [70]
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8 0
3 years ago
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What is the number of subsets of S= {1, 2, 3…10} that contain five element include 3 or 4 but not both?
Ivenika [448]

Answer:

140

Step-by-step explanation:

To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.

First, let's count the number of subsets that contain the element 3.

Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is {}_8C_4=70.

Now, let's count the number of subsets that contain the element 4.

4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in {}_8C_4=70 ways.

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7 0
3 years ago
Kevin has already read 45 pages in his novel for English. He can read roughly 20 pages each hour. Shania has only read 5 pages s
jolli1 [7]

Answer:

Shania has read the most pages.

Step-by-step explanation:

Following the formula y = mx + b.

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y = mx + 45

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y = 20x + 45

Shania already read 5 pages

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y = 25x + 5

We need to find out how many pages they read after 20 hours, plug 20 into x.

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20(20) + 45 =

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445

Shania

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Shania read 60 more pages than Kevin.


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3 years ago
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Answer:

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A square fulfills all the requirements to become a rhombus:

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