Find the circumference of the whole circle,divide by 4,and then add the radius twice.
Answer:
Step-by-step explanation:
Triangles PQR and PSR are right triangles, with both QR = SR = 5 (since these are radii of the circle R).
TR is also a radius of the circle, so TR = 5, making PR = 4 + TR = 9.
Because PQR and PSR are right triangles, we can compute the length of the missing side, which will be equal. By the Pythagorean theorem,
PQ^2 + QR^2 = PR^2
PQ^2 + 5^2 = 9^2
PQ^2 = 56
PQ = √56 = 2√14
Then the perimeter of PQRS is
PQ + QR + RS + SP = 2√14 + 5 + 5 + 2√14 = 10 + 4√14
and so the answer is B.
9514 1404 393
Answer:
109°
Step-by-step explanation:
You always start a problem by taking a careful look at the information given and how it relates to what is asked. Here, the key information is in the symbols marking the lines PQ and RS. They are parallel.
This means segments QR and PS are transversals. Marked angle 41° will be an "alternate interior angle" with angle TPQ, so angle TPQ is also 41°.
The desired angle, PTR, is an exterior angle to ΔQTP, so its measure is the sum of remote interior angles TQP (68°) and TPQ (41°). That is, ...
∠PTR = ∠TQP +∠TPQ = 68° +41°
∠PTR = 109°
A or B. its a 50/50 here. I can't really tell whats on the graph.
