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3 years ago

1. 35x^3 + 5x^2+ 28x + 4

Mathematics

1 answer:

pishuonlain [190]3 years ago

6 0

It rlly is possible if u dont have the value for x or what it's equal at the end

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Solve x^2 + 5x + 6 = 0

grigory [225]

Answer:

(x+3)(x+2)

Step-by-step explanation:

take x^2 and take it apart. so it should be (x+ ) (x+ ) then take 6 and make it so it's multipuls equal 5. ur answer should be (x+3)(x+2) or vice versa.

4 0

3 years ago

Read 2 more answers

I need help asap!!

Elza [17]

Similar triangles that have a scale ratio other than 1 are not congruent triangles.

The true statement about the proportions of the sides is $\frac{AC}{DF} = \frac 52$

The scale ratio is given as: 5 : 2

And the corresponding sides are given as:

AB and DE.
BC and EF.
CA and FD.

The above highlights mean that,

$\frac{AC}{DF} = \frac{BC}{EF} = \frac{AB}{DE} = \frac 52$

Hence, the true statement is $\frac{AC}{DF} = \frac 52$

Read more about similar triangles at:

brainly.com/question/14285697

4 0

3 years ago

(-12+(-5)? what is the sum

Roman55 [17]

We know when adding a negative and a negative, it will make the negative number bigger

So, (-12) + (-5) = -17

Hope this helps you

Brainliest would be appreciated

-AaronWiseIsBae

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3 years ago

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Even the measure ofAngle six is 62 what is the measure of angle five

Agata [3.3K]

Step-by-step explanation:

If you look closely at this image, you can see that ∠6 and ∠5 together will be equal to line c.

A straight line is equal to 180 so if we do...

$180-62$

= 118.

<u>∠5 will be equal to 118.</u>

If we go even further, because vertical angles are congruent...

∠7 = 62

∠8 = 118

8 0

3 years ago

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In a random sample of 80 teenagers, the average number of texts handled in one day is 50. The 96% confidence interval for the me

Naily [24]

Answer:

Standard deviation of the sample = 17.421

Step-by-step explanation:

We are given that in a random sample of 80 teenagers, the average number of texts handled in one day is 50.

Also, the 96% confidence interval for the mean number of texts handled by teens daily is given as 46 to 54.

So, sample mean, $xbar$ = 50 and Sample size, n = 80

Let sample standard deviation be s.

96% confidence interval for the mean number of texts, $\mu$ is given by ;

96% confidence interval for $\mu$ = $xbar \pm 2.0537*\frac{s}{\sqrt{n} }$

[46 , 54] = $50 \pm 2.0537*\frac{s}{\sqrt{80} }$

Since lower bound of confidence interval = 46

So, 46 = $50 - 2.0537*\frac{s}{\sqrt{80} }$

50 - 46 = $2.0537*\frac{s}{\sqrt{80} }$

s = $\frac{4*\sqrt{80} }{2.0537}$ = 17.421

Therefore, standard deviation of the sample is 17.421 .

3 0

4 years ago