Answer:
a: no solutions
b: (2, 3)
Step-by-step explanation:
a:
In both equations, the slope of x is the same, but the y-intercept is not, which means they are parallel. Therefore, this system of equations has no solutions.
b:
Since both of the equations are equal to y, we can set them equal to each other:
We can solve by factoring (by finding a number that multiplies to 4 and adds up to -4):
(x-2)^2 = 0
x = 2
Now, to find y, plug-in x to any of the equations:
y = 2*2-1 = 3
Therefore, the solution to this system of equation is (2, 3)
I hope this helped.
Answer:
he area that is un-shaded is (x-3)(x-6).
The entire area is (2x+2)(3x-4).
Area of the shaded region is:
(2x+2)(3x-4) - (x-3)(x-6) =
(6x2-2x-8) - (x2-9x+18) =
6x2-2x-8-x2+9x-18 =
5x2+7x-26 hopes this help btw (;
Answer:
Please find attached the drawing of quadrilateral KLMN created with MS Whiteboard using the Ink to Shape command
(a) Two pairs of opposite sides are 
, 
and 
, 
(b) Two pairs of opposite angles are ∠LKN, ∠LMN, and ∠KLM and ∠KNM
(c) Two pairs of adjacent sides are , and ,
(d) Two pairs of adjacent angles are ∠LKN, ∠KLM and ∠LMN, ∠KNM
Step-by-step explanation:
Part A:
Let the length of one of the sides of the rectangle be L, then the length of the other side is obtained as follow.
Let the length of the other side be x, then
Thus, if the length of one of the side is x, the length of the other side is 8 - L.
Hence, the area of the rectangle in terms of L is given by
Part B:
To find the domain of A
Recall that the domain of a function is the set of values which can be assumed by the independent variable. In this case, the domain is the set of values that L can take.
Notice that the length of a side of a rectangle cannot be negative or 0, thus L cannot be 8 as 8 - 8 = 0 or any number greater than 8.
Hence the domain of the area are the set of values between 0 and 8 not inclusive.
Therefore,
