Ask question

Ask question

All categories

tekilochka [14]

3 years ago

15

Rewrite 1/2 x 1/2 as an exponential expression with a base of 2

1 answer:

11111nata11111 [884]3 years ago

3 0

Answer:

1/4

Step-by-step explanation:

You might be interested in

For which acute angle are the sine of the angle and cosine of the angle equal? 30º 45º 60º 75º

Damm [24]

Hello

sin ..... | 0° |30°|45°|60°|90°|
...........| 0...| 1..| 2..| 3..| 4..| write numbers
...........| 0...| 1..|√2.| √3 | 2..| take root square
...........| 0...|1/2|√2/2|√3/2|1| divide by 2
...........| 0...|1/2|√2/2|√3/2|1| .....
cos.....| 90°|60°|45°|30°| 0°|

sin (75°)
=sin(30°+45°)=sin 30°*cos 45° +cos 30°*sin 45°
.................... =1/2*√2/2 + √3/2*√2/2
.................... = √2(1+√3)/4

cos 75°
=cos(30°+45°)=cos 30°*cos 45°-sin 30°*cos 45°
=√3/2*√2/2-1/2*√2/2
=√6/4-√2/4=√2/4*(√3 -1 )

5 0

3 years ago

I need help I will give 100 points and brainliest

Anit [1.1K]

Answer:

5. 9/2 6. 9/4 7. 7/2 8. 8/3 9. 2/3

Step-by-step explanation:

Hope I helped!!

4 0

3 years ago

Read 2 more answers

Choose the correct converse.

a_sh-v [17]

Answer:

i think it is B i am not sure

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

At the beginning of the month,Kimberly had $65.78. Since then,she has received three payments of $32.50 from her babysitting job

ivann1987 [24]

Answer:

98.28

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the smallest possible value of$$\frac{(y-x)^2}{(y-z)(z-x)} \frac{(z-y)^2}{(z-x)(x-y)} \frac{(x-z)^2}{(x-y)(y-z)},$$where $x

Harlamova29_29 [7]

Answer:

$\frac{(y-x)^2}{(x-y)^2} \frac{(x-z)^2}{(z-x)^2}\frac{(z-y)^2}{(y-z)^2} =1$

And on this case the samllest possible value would be 1

Step-by-step explanation:

For this case we have the following expression:

$\frac{(y-x)^2}{(y-z)(z-x)} \frac{(z-y)^2}{(z-x)(x-y)} \frac{(x-z)^2}{(x-y)(y-z)}$

And we can rewrite this expression like this:

$\frac{(y-x)^2}{(x-y)^2} \frac{(x-z)^2}{(z-x)^2}\frac{(z-y)^2}{(y-z)^2}$

For this case is important to remember the following property from algebra:

$(a-b)^2 = a^2 -2ab + b^2$

$(b-a)^2 = b^2 - 2ab + a^2$

On this case we can see that $(a-b)^2 = (b-a)^2$

So then $(y-x)^2 = (x-y)^2 , (x-z)^2= (z-x)^2, (z-y)^2 =(y-z)^2$

So then we can simplify all the expression and we got this:

$\frac{(y-x)^2}{(x-y)^2} \frac{(x-z)^2}{(z-x)^2}\frac{(z-y)^2}{(y-z)^2} =1$

And on this case the samllest possible value would be 1

3 0

3 years ago