Xy + 6e^y = 6e
taking first derivative :
<span>xy' + y + 6y(e^y)(y') = 0 </span>
<span>xy" + y' + y' + 6y'(e^y)(y') + 6yy(e^y)y' + 6y(e^y)y" = 0 </span>
<span>Put x = 0,
0 + 6e^y = 6e,
y = 1 </span>
<span>0 + 1 + 6(1)(y')e = 0,
Put y' = 0 </span>
<span>0 + 0 + 0 + 0 + 0 +6 ey" = 0,
y" = 0</span>
Answer:
the answer is 5+4× and ur welcome
Answer: The function that models the distance they drive is
f(x) = 50x + 20 where x is the time in hours
reasonable domain: 0 ≤ x ≤ 3
Step-by-step explanation:
examples:
95 = 50(1.5) + 20 After driving another hour and a half, they will have driven a total of 95 miles.
120 = 50(2) + 20 This means that after 2 more hours they will reach their destination.
There is a little ambiguity in the question. The function could be written as if they are starting out. f(x) = 50t
20 = 50(.4) At 50 mph it took .4 hours to go 20 miles.
120 = 5(2.4) The whole trip took 2.4 hours.
Answer:
(-1.5,-16)
(1,4)
(2.5,-3)
Step-by-step explanation:
Over the interval (-3,0], the local minimum is (-1.5,-16).
Over the interval [0,3], the local maximum is (1,4).
Over the interval [0,57 , the local minimum is (2.5,-3).
Average speed = total distance divided by total time.
In the first part, the car covered 490 km in 7 hours, but I think you mistyped the second part (“then covers a speed of 90km”) and a critical piece is missing to find the total distance and time.
