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irakobra [83]
3 years ago
14

The monthly cost (in dollars) of a long-distance phone plan is a linear function of the total calling time (in minutes). The mon

thly cost for 31 minutes of calls is
$18.25 and the monthly cost for 44 minutes is $19.42. What is the monthly cost for 33 minutes of calls?
Mathematics
1 answer:
kupik [55]3 years ago
8 0

Answer:

The cost is;

$18.43

Step-by-step explanation:

The general model for a linear equation is;

y = mx + b

let y be the monthly cost in dollars

x is the number of minutes

b will represent the base cost

m is the cost of the call per minute

so let us get m and b

Thus, we have;

18.25 = 31m + b

19.42 = 44m + b

Subtract i from ii

(19.42-18.25) = (44-31)m

1.17 = 13m

m = 1.17/13 = 0.09

To get b, we substitute the value of m in any of the equation

18.25 = 31 m + b

18.25 = 31(0.09) + b

b = 18.25 - 2.79

b = 15.46

so, the equation of the line is;

y = 0.09x + 15.46

Now to get the cost for 33 minutes

simply substitute the value of 33 for x

we have this as;

y = 0.09(33) + 15.46

y = $18.43

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Answer:

12.2*1=12.2

12.2*0.45=5.49

5.49+12.2=17.69

Step-by-step explanation:

5 0
3 years ago
What’s the 5th term is 2,14,98
iragen [17]

\bold{\huge{\orange{\underline{ Solution }}}}

<h3><u>Correct </u><u>Question </u><u>:</u><u>-</u></h3>

What is the 5th term of an AP 2 , 14 ....98 .

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

<u>We </u><u>have </u><u> </u><u>AP</u><u>, </u>

  • \sf{ 2 , 14 ,.... 98 }
  • <u>AP </u><u>is </u><u>the </u><u>arithmetic </u><u>progression </u><u>or </u><u>a </u><u>sequence </u><u>of </u><u>numbers </u><u>in </u><u>which </u><u>succeeding </u><u>number </u><u>is </u><u>differ </u><u>from </u><u>preceeding </u><u>number </u><u>by </u><u>a </u><u>common </u><u>value</u><u>. </u>

<h3><u>Solution </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>an </u><u>AP </u><u>:</u><u>-</u><u> </u><u>2</u><u> </u><u>,</u><u> </u><u>1</u><u>4</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>9</u><u>8</u>

<u>Therefore</u><u>, </u>

  • \sf{a1\: or \:1st\: term = 2 }
  • \sf{a2 \:or \:2nd\: term = 14 }
  • \sf{an \:or\: last\: term = 98}

<u>Here</u><u>, </u>

Common difference of an AP

\sf{ a2 - a1 }

\sf{ = 14 - 2}

\sf{ = 12}

Thus, The common difference is 12

<u>Now</u><u>, </u>

We know that,

\sf{an = a1 + ( n - 1 )d}

\sf{a5 = 2 + ( 5 - 1 )12}

\sf{a5 = 2 + 4 × 12}

\sf{a5 = 2 + 48}

\sf{\red{a5 = 50}}

Hence, The 5th term of given AP is 50

4 0
2 years ago
Use the data to create a scatter plot\<br> forks: 2,4,6,8,10,12<br> spoons: 10,6,4,1,0,2
Len [333]

Answer:

The resulting scatter plot is attached below :

To plot the required scatter plot :

We first take forks on the x - axis and the spoons on the y - axis

Now we arrange the given data in the form of x and y coordinates

Hence, the data becomes :

(2, 10)

(4, 6)

(6, 4)

(8, 1)

(10, 0)

(12, 2)

Now, We plot these points on the graph and get the required scatter plot for the given data.

5 0
3 years ago
False
dedylja [7]
It’s true you can give the other person it tho
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2 years ago
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pashok25 [27]
Area=length x width
A=10x(3/2 x + 1/2 y).
Now Distribute...
A=30x^2/2 + 10xy/2)
Now simplify fractions...
A=15x^2 + 5xy= 125

So I believe your answer is D)
7 0
3 years ago
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