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3 years ago

Which statements regarding the diagram Triangle EBC are true? Select three options

Mathematics

2 answers:

Fynjy0 [20]3 years ago

6 0

Answer:

The answer would be:

B. ∠DEC is an exterior angle.

Step-by-step explanation: Your welcome

tekilochka [14]3 years ago

3 0

Answer:

∠DEC is an exterior angle.

∠ABE and ∠EBC are supplementary angles.

∠BEC is a remote interior angle to exterior ∠BCF.

Step-by-step explanation:

hope this helps

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Rita earns $10 per hour. She puts 5% of her earnings in savings. Write an inequality to find how many hours h Rita must work to

xz_007 [3.2K]

Find the percentage. 5 percent of 10 is 0.5. 50 cents.
25 X 2(AMOUNT OF 5 PERCENT OF A DOLLAR IN A DOLLAR) = 50.

50 hours

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3 years ago

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What is the area of this trapezoid?

Sonbull [250]

Find the area of the square first
Area = Length x Width
Area = 12 x 9
Area = 108

Find the area of the right triangles
Area = 1/2(Length x Base)
Area = 1/2(9 x 2)
Area = 1/2(18)
Area = 9
Since there is 2 triangles multiply by 2
9 x 2 = 18

Now add
108 + 18 = 126
126 is your area

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3 years ago

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Morton made 36 out of 48 free throws last season. What percent of his free throw did Morton make?

sveta [45]

Just divide 36 by 48, and you will get that he made 75% of his free throws.

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3 years ago

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15. Before oil is added to a certain road surface material, the other ingredients are mixed. The mixture contains

mojhsa [17]

Answer:

sand = 3450 pounds

3/4 inch stones =6750 pounds

1 inch stones =4800 pounds.

Step-by-step explanation:

The mixture composition is :

45% three-quarter inch stones

32% inch stones and

sand for balance

The percent here is by mass of material used.

Weight of mixture is 15,000 pounds before oil addition.

Use the percent by weight for the two types of stones and calculate real values in pounds

Formula to apply is:

Mass percent = (mass of a material/ total mass of mixture) * 100

For 3/4 inch stones it will be:

$0.45= \frac{x}{15000} *100\\\\0.45=\frac{x}{150} \\0.45*150=x\\x=6750$

The 3/4 inch stones weigh 6750 pounds

The 1 inch stones will be

$32/100 * 15000 =4800$

The 1 inch stones weigh = 4800 pounds

Total for the two items : 4800+6750 =11550 pounds

The sand used weighs : 15000 - 11550 = 3450 pounds

8 0

3 years ago

Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0

andreev551 [17]

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==> sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0 or sin(2x) = 0 or 2 cos(2x) + 1 = 0

sin(5x) = 0 or sin(2x) = 0 or cos(2x) = -1/2

sin(5x) = 0 ==> 5x = arcsin(0) + 2nπ or 5x = arcsin(0) + π + 2nπ

… … … … … ==> 5x = 2nπ or 5x = (2n + 1)π

… … … … … ==> x = 2nπ/5 or x = (2n + 1)π/5

sin(2x) = 0 ==> 2x = arcsin(0) + 2nπ or 2x = arcsin(0) + π + 2nπ

… … … … … ==> 2x = 2nπ or 2x = (2n + 1)π

… … … … … ==> x = nπ or x = (2n + 1)π/2

cos(2x) = -1/2 ==> 2x = arccos(-1/2) + 2nπ or 2x = -arccos(-1/2) + 2nπ

… … … … … … ==> 2x = 2π/3 + 2nπ or 2x = -2π/3 + 2nπ

… … … … … … ==> x = π/3 + nπ or x = -π/3 + nπ

(where n is any integer)

5 0

3 years ago