Find all the prime factors of the three numbers. pick up the common factors, ONCE, then pick up the non-common factors one by one, multiply the factors, the product is the least common factor.
example: the least common multiple of 6, 8, and 15
6=2*3
8=2*2*2
15=3*5
Note: do not write 8 into 4*2, because 4 is not a prime number. you have to break the number down to prime factors only.
Notice that 6 and 8 have a common factor 2, so pick up the 2;
6 and 15 have a common factor of 3, so pick up the 3.
those are the only two shared factors, so 2×3
now pick up whatever is not shared:
the two 2s for 8 and the 5 for 15 is not shared, add 2, 2, and 5 to the multiplication: 2×3×2×2×5=120
120 is the least common multiples of 6,8, and 15
this is basically how it is done. I believe you can explain better in your own words.
The area of a right triangle with side lengths 7 and 7 is 
Following with the extra hint that x = 82.03 m
There are 2 ways to approach the question, but although I prefer to group up x first before plugging value, having that -0.05x^2 to group up is too annoying:
Plug x = 82.03
=> Y = -0.05*(82.03^2) + 4.5*82.03 - 6.5
= -336.446045 + 369.135 - 6.5
= 26.188955 m
Please take the time and understand the answer instead of just looking at the final result.
Also I know the number is very long, but that's the question's fault. <span>¯\_(ツ)_/¯</span>
Answer:
Attached please find answer
Step-by-step explanation:
= (x² + x - 42) / (x - 6)
= [x² + (7x - 6x) - 42] / (x - 6)
= [x² + 7x - 6x - 42] / (x - 6)
= [(x² + 7x) - (6x + 42)] / (x - 6)
= [x(x + 7) - 6(x + 7)] / (x - 6)
= [(x + 7)(x - 6)] / (x - 6)
= x + 7 → when x approches 6
= 6 + 7
= 13
Other method:
Lim (x² + x - 42) / (x - 6)
x→ 6
When x → 6, there is an indeterminate expression because: 6 - 6 = 0
Do you know the l'Hôpital's rule, when x → a:
Lim [ f(x) / g(x) ] = Lim [ f'(x) / g'(x) ]
f(x) = x² + x - 42
f'(x) = 2x + 1
g(x) = x - 6
g'(x) = 1
= f'(x) / g'(x)
= (2x + 1)/1
= 2x + 1 → when x approches 6
= 12 + 1
= 13
Answer:
b = 7
Step-by-step explanation:
6 b + 6 = 48
Subtract 6 from each side
6b+6-6 = 48 -6
6b = 42
Divide each side by 6
6b/6 = 42/6
b = 7
