Answer:
- plane: 530 mi/h
- wind: 40 mi/h
Step-by-step explanation:
Let p and w represent the speeds of the plane and the wind. The relation between time, speed, and distance is ...
speed = distance/time
p +w = (2565 mi)/(4.5 h) = 570 mi/h
p -w = (2205 mi)/(4.5 h) = 490 mi/h
Adding these speeds, we get ...
(p +w) +(p -w) = (570) +(490) mi/h
2p = 1060 mi/h
p = 530 mi/h
Then the speed of the wind is ...
w = 570 mi/h -p = (570 -530) mi/h = 40 mi/h
The plane's speed is 530 mi/h; the wind speed is 40 mi/h.
I think it’s answer B. Because % to decimal is 6.14% divided by 100 so the decimal would move to the left two places which in 0.0614
I now completely sure but I think that’s right
Answer:



Step-by-step explanation:
We know that:
Only employees are hired during the first 3 days of the week with equal probability.
2 employees are selected at random.
So:
A. The probability that an employee has been hired on a Monday is:
.
If we call P(A) the probability that 2 employees have been hired on a Monday, then:

B. We now look for the probability that two selected employees have been hired on the same day of the week.
The probability that both are hired on a Monday, for example, we know is
. We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.
So
.
C. If the probability that two people have been hired on a specific day of the week is
, then the probability that 7 people have been hired on the same day is:

D. The probability is
. This number is quite close to zero. Therefore it is an unlikely bastate event.
Answer:
No
Step-by-step explanation:
I don' think that Y varies directly like X does because first they're different numbers. Y=1.2 and X=1.6.