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2 years ago

What are the zero(s) of the function f(x) = the quantity of 5 x squared minus 25 x, all over x ? (2 points)

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

8 0

Answer:

Five

Step-by-step explanation:

5x square minus 25x=0

Divide by x gives 5x - 25=0

X=5

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Steps to solve x/8-5=-1

topjm [15]

Answer: x = 32

Step-by-step explanation:

x/8 - 5 = -1

Add 5 both sides : x/8 = 4

Multiply both sides by four: x=4 times 8

4 0

2 years ago

Write an equation of a line in slope intercept form with the given slope and the y-intercept.

defon

The way you put it is confusing. I'll answer but the way you put it was confusing to me.

7 0

3 years ago

The perimeter of a pool is 96 feet. If the length of the pool is 3 times its width, what is the width of the pool? Labeling the

k0ka [10]

Answer:

12 feets

Step-by-step explanation:

Let the area of the pool be Length×width

There will be 2lengths and 2widths as well so the perimeter of the pool will be the addition of all the sides of the pool i.e 2L + 2W = 96... (1)

And since the length of the pool is 3 times its width, we have

L = 3W... (2)

Substituting equation 2 into 1 to get the width 'W'

2(3W) + 2W = 96

6W + 2W = 96

8W = 96

W = 96/8

W = 12feets

The width of the pool is 12feets

4 0

3 years ago

^^^^<br> please help :)))

ikadub [295]

2x-1.1/4+x/3=2

2x-1/4+x/3=2

2x-1/4+x/3+1/4=2+1/4

2x+x/3=9/4

3(2x+x/3)=3.94

7x=27/4

7x/7=27/4/7

x=27/8

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7 0

2 years ago

WILL GIVE BRAINLIEST

stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph. A cargo plane left sometime later flying in the same direction at an average speed of 207 mph. After flying for 5.3 hours the cargo plane caught up with the Air Force plane.

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, $\text { distance travelled }=\text { speed } \times \text { time }$

For air force plane $\rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }$

$\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }$

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, $159 \times \text { time taken by air force plane }=207 \times 5.3$

$\Rightarrow =\frac{207 \times 5.3}{159}$

$\Rightarrow =\frac{1097.1}{159}$

Time taken by air force plane = 6.9 hrs

6 0

3 years ago