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3 years ago

Can some one please help me and explain how you got the answer?

Mathematics

2 answers:

podryga [215]3 years ago

7 0

Answer:

Yes number 5 is, they are proportional because y is coresponding to x by multiplying by 1/5

No number 6 isn't, you can't go from 3 to 1 and 7 to 3

yulyashka [42]3 years ago

4 0

Answer:

5. Proportional & 6. Not Proportional

Step-by-step explanation:

Proportional relationships = x and y increase at the same rate

5. all increases by x2

6. increases at different rates

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A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro

pshichka [43]

Answer:

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed $\frac{dx}{dt}$ = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

$(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=(x)\frac{dx}{dt}$

$(h)\frac{dh}{dt}=rx$

$\frac{dh}{dt}=\frac{rx}{h}$

When automobile is 30 miles past the intersection,

For x = 30

$\frac{dh}{dt}=\frac{30r}{h}$

Since $h=\sqrt{d^{2}+(30)^{2}}$

Therefore,

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}$

$\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}$

3 0

3 years ago

The morning absentee report shows that 15% of the students are absent. There are 1360 students enrolled in the school. how many

Murrr4er [49]

In order to find the answer you multiply 1360 by .15 and you get the answer of 204. So 204 students are absent.

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Answer:

if she does so multiply by seven to get final answer

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2 years ago

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24lbs of potatoes cost $288. How much would 29lbs cost?

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300 dollars
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Daniel [21]

Answer:

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Step-by-step explanation:

it will be a rectangle with the dimension of diameter and height of the cylinder

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