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3 years ago

Please put the missing numbers pls irl give brainliest

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

8 0

Answer: (9 x 10^10) - (4 x 10^10) in scientific notation is 5x x 10^10

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Find the median of the data set: -66, -48, -52, -42

olga2289 [7]

-66, -52, - 48, -42

If you can have 2 medians (since there is only 4 numbers), it is -52 and -48

If you can only have one,then i believe you choose -50, because it is in between -48 and -52

hope this helps

6 0

3 years ago

Help me with these two questions plz

aleksandr82 [10.1K]

Since it says m1 is 120 and it says find m3 don’t you need to multiply or I’m wrong

6 0

3 years ago

.What is answer pls help me with this very important question. 9 + 10 (78) =

Korolek [52]

Answer:

789

Step-by-step explanation:

9+10(78)

9+10*78

9+780

789

6 0

3 years ago

Read 2 more answers

Combine like terms to create an equivalent expression -1/2(-3y+10)

marysya [2.9K]

Answer:

3/2y - 5

Step-by-step explanation:

-1/2(-3y+10)

Expand the brackets.

-1/2(-3y) -1/2(10)

Multiply.

3/2y - 5

3 0

3 years ago

Read 2 more answers

Please help me I need help please

MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

$x^2+(p-3)y^2-4x+6y-16=0$

Standard equation of a circle:

$(x-a)^2+(y-b)^2=r^2$

(where $(a,b)$ is the centre of the circle, and $r$ is the radius)

If you expand this equation, you will see that the coefficient of $y^2$ is always one.

Therefore, $p-3=1$

$\implies p=1+3=4$

Additional information

To rewrite the given equation in the standard form:

$\implies x^2+y^2-4x+6y-16=0$

$\implies x^2-4x+y^2+6y=16$

$\implies (x-2)^2-4+(y+3)^2-9=16$

$\implies (x-2)^2+(y+3)^2=16+4+9$

$\implies (x-2)^2+(y+3)^2=29$

So this is a circle with centre (2, -3) and radius √29

3 0

2 years ago