Lets solve f(5). First, replace all "n"s in the equation with 5s. F(5+1)=F(5)-2. This means that F(6)=F(5)-2, F(5)=F(4)-2, F(4)=F(3)-2, F(3)=F(2)-2, and F(2)=F(1)-2. Because we know F(1)=18, F(2)=16, F(3)=14, F(4)=12, and F(5)=10.
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<h3>Total number of students in Ms. Perron’s class is 25</h3>
<em><u>Solution:</u></em>
In Ms. Perron’s class, 40% of the students are boys
There are 10 boys in the class
Let "x" be the total number of students in Perron class
From given,
40 % of total students are boys
Therefore,
40 % of x = 10
Thus total number of students in Ms. Perron’s class is 25
24x−6y=18 Step 1: Add 6y to both sides. 24x−6y+6y=18+6y24x=6y+18
Step 2: Divide both sides by 24.24x24=6y+1824x=14y+34
Answer: x=14y+34