Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
Answer:
61 Students.
Step-by-step explanation:
So you need to find 20% of 305. You can do this by dividing by 5.
305 divided by 5 equals 61.
If you have questions, ask please :)
Answer:
25 boxes because if you divide 590 from 23.25 it equals 25. I got 590 by subtracting 650 and 60 to make sure there is still that remaining 60 in the supply account.
Step-by-step explanation:
Answer:
37.5%
Step-by-step explanation:
If you take 6 and divide it by 16, you will get 0.375. You then have to move the decimal two places to the left to get the percentage.
Answer:
Step-by-step explanation:
Given A (x₁, y₁) = ( -6, 7) and B (x₂, y₂) = (-3, 6)
Slope of line passing through points ( -6, 7) and (-3, 6) is:
m = 
Now, the equation of line in point-slope form:
(y - y₁) = m (x - x₁)
Substituting the value of m and (x₁, y₁) = ( -6, 7) in above equation,
Option B is the correct answer.
