Answer:
f(4)=-3
Step-by-step explanation:
f(1)=2
f(n)=f(n-1)^2-n
If n=2
f(2)=f(2-1)^2-2
f(2)=f(1)^2-2
f(2)=2^2-2
f(2)=4-2
f(2)=2
If n=3
f(3)=f(3-1)^2 - 3
f(3)=f(2)^2 - 3
f(3)=2^2-3
f(3)=4-3
f(3)=1
if n=4
f(4)=f(4-1)^2 - 4
f(4)=f(3)^2 - 4
f(4)=1^2 - 4
f(4)=1-4
f(4)=-3
Yes, you can see by subtracting 32 from the bottom sides and seeing that the correspondent for 20 degrees celcius is double that of the correspondent for 10 degrees celcius
A=1 B=2 C=3 Yes it would work for all because its using the commutative property.
Factor the equation to give
By the zero product property, either x^2=0 or (3x^2+12-6x)=0 or both.
If x^2=0, then x=0
if (3x^2+12-6x)=0, we use the quadratic formula to solve for x
where x=1 ± √ (3) i
Answer: the roots of <span>3x^4+12x^2=6x^3 are {0 (multiplicity 2), 1+√3 i, 1-√3 i}</span>
Answer:
- The mean for Group A is less than the mean for Group B.
- The median for Group A is less than the median for Group B.
- The mode for Group A is less than the mode for Group B.
Step-by-step explanation:
First, we can find the measures of center for each group.
<u>Group A</u>
Mode: 1
Median: (1 + 2) / 2 = 3 / 2 = 1.5
Mean: (1 * 5 + 2 * 4 + 3) / 10 = (5 + 8 + 3) / 10 = 16 / 10 = 1.6
<u>Group B</u>
Mode: 3
Median: 92 + 3) / 2 = 5 / 2 = 2.5
Mean: (1 * 3 + 2 * 2 + 3 * 4 + 5) / 10 = (3 + 4 + 12 + 5) / 10 = 24 / 10 = 2.4
From here, we can see that...
- The mean for Group A is less than the mean for Group B.
- The median for Group A is less than the median for Group B.
- The mode for Group A is less than the mode for Group B.
Hope this helps!
