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olganol [36]
3 years ago
11

PLEASE HELP Find the length of PQ in circle R to the nearest hundredths

Mathematics
1 answer:
Vladimir [108]3 years ago
5 0
There's no way to do that without seeing the drawing or hearing a lot more information. For one thing, we don't even know the size of the circle yet.
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What is the measure of the indicated angle? 37∘ 53∘ 180∘ 127∘
Hoochie [10]

Answer:

53∘

plz mark me as brainliest.

4 0
3 years ago
What is the inverse of y= 3/2x -2
Mashcka [7]

Answer:

f^-1(x) =  (2x + 4) / 3

         

Step-by-step explanation:

- switch 'y' with 'x'

x = 3/2y - 2

- solve for 'y'

x + 2 = 3/2y

- multiply each side by 2

y = (2x + 4) / 3

3 0
3 years ago
Please answer these 6 questions
Triss [41]
1. You would add 5 to -14, getting -9, which leaves you with 3x=-9. You would then divide -9 by 3, leaving you with x=-3.
2. First, subtract 22 from 10, getting -12=-2c. Next divide -12 by -2, leaving you with 6=c.
3. Add 17 to 18 to get 35=-5b. Then divide 35 by -5, leaving you with -7=b.
4. Subtract 12 from -12, giving you -24=-8x. Then divide 24 by 8, giving you 3=x.
5. Add .03 to -9, giving you 1.3n= -8.97. Divide-8.97 by 1.3 to get n=-6.9.
6. Subtract 7/9 from 2/9 leaving you with -5/9=-5/11h. Divide and get h=1 and 2/9.
Hope this helped! : )
4 0
3 years ago
In auto racing a pit stop is is where a racing vehicle stops for new tires and repairs and other mechanical adjustments. The eff
Dahasolnce [82]

Answer:

a) H_{0}: t=13 seconds

   H_{a}: t<13 seconds

b) At α= 0.01, one-tailed critical value is -2.33

c) Test statistic is −2,98

d) since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.

Step-by-step explanation:

according to the web search, the question is missing some words, one part should be like this:

"A pit crew claims that its mean pit stop time ( for 4 new tires and fuel) is less than 13 seconds."

Let t be the mean pit stop time of the pit crew.

H_{0}: t=13 seconds

H_{a}: t<13 seconds

At α= 0.01, one-tailed critical value is -2.33

Test statistic can be calculated using the equation:

z=\frac{X-M}{\frac{s}{\sqrt{N} } } where

  • X is the sample mean pit stop time (12.9 sec)
  • M is the mean pit stop time assumed under null hypothesis (13 sec)
  • s is the population standard deviation (0.19 sec.)
  • N is the sample size (32)

Then z=\frac{12.9-13}{\frac{0.19}{\sqrt{32} } } ≈ −2,98

since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.

8 0
3 years ago
a candy factory made 54 boxes of chocolate each box weigh 2 pounds they pack the boxes and 6 cases with the same number of vodka
Citrus2011 [14]

Answer:

18 pounds of chocolate

Step-by-step explanation:

54 boxes divided among 6 cases means each case held 54/6 = 9 boxes.

Each box weighs 2 pounds, so 9 boxes (in 1 case) weigh 9·2 = 18 pounds.

4 0
4 years ago
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