Answer:
53∘
plz mark me as brainliest.
Answer:
f^-1(x) = (2x + 4) / 3
Step-by-step explanation:
- switch 'y' with 'x'
x = 3/2y - 2
- solve for 'y'
x + 2 = 3/2y
- multiply each side by 2
y = (2x + 4) / 3
1. You would add 5 to -14, getting -9, which leaves you with 3x=-9. You would then divide -9 by 3, leaving you with x=-3.
2. First, subtract 22 from 10, getting -12=-2c. Next divide -12 by -2, leaving you with 6=c.
3. Add 17 to 18 to get 35=-5b. Then divide 35 by -5, leaving you with -7=b.
4. Subtract 12 from -12, giving you -24=-8x. Then divide 24 by 8, giving you 3=x.
5. Add .03 to -9, giving you 1.3n= -8.97. Divide-8.97 by 1.3 to get n=-6.9.
6. Subtract 7/9 from 2/9 leaving you with -5/9=-5/11h. Divide and get h=1 and 2/9.
Hope this helped! : )
Answer:
a)
: t=13 seconds
: t<13 seconds
b) At α= 0.01, one-tailed critical value is -2.33
c) Test statistic is −2,98
d) since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.
Step-by-step explanation:
according to the web search, the question is missing some words, one part should be like this:
"A pit crew claims that its mean pit stop time ( for 4 new tires and fuel) is less than 13 seconds."
Let t be the mean pit stop time of the pit crew.
: t=13 seconds
: t<13 seconds
At α= 0.01, one-tailed critical value is -2.33
Test statistic can be calculated using the equation:
where
- X is the sample mean pit stop time (12.9 sec)
- M is the mean pit stop time assumed under null hypothesis (13 sec)
- s is the population standard deviation (0.19 sec.)
- N is the sample size (32)
Then
≈ −2,98
since -2.98<-2.33, we can reject the null hypothesis. There is significant evidence that mean pit stop time for the pit crew is less than 13 seconds at α= 0.01.
Answer:
18 pounds of chocolate
Step-by-step explanation:
54 boxes divided among 6 cases means each case held 54/6 = 9 boxes.
Each box weighs 2 pounds, so 9 boxes (in 1 case) weigh 9·2 = 18 pounds.