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atroni [7]
3 years ago
13

Find the domain (d) range(r) and asymptote (a) of the graph f(x)=5^x+6

Mathematics
1 answer:
Temka [501]3 years ago
7 0

Answer:

D= R

R =(6,∞)

A: y=6

Step-by-step explanation:

We are asked to Find the domain (D ) range(R) and Asymptote (A) of the graph f(x)=5^x+6

Our function f(x)=5^x+6 is an translated function of

f(x)=5^x which is an exponential function. Therefore the basic properties remains the same.

Any exponential function is defined for all values of x and Hence

c

however, The range of exponential functions is always positive from 0 to infinity . however here we have 6 added to out parent exponential function and hence the Range of exponential function is always be

Range = (6,∞)

Asymptote : Asymptote of our parent exponential  function is y = 0, but in our function f(x)=5^x+6 , the asymptote will be y=6

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Jimmy invests $7,000 in an account that pays 3% interest compounded semi-annually. What is his balance after 8 years?
Bumek [7]

Answer:

$8882.9

Step-by-step explanation:

A=p(1+(r/n))^nt

Given:P=7000, r=(3÷100%)=0.03 , n=2, t=8

A = 7000(1+(.03/2))^(2×8)

A = 7000 (1+0.015)^16

A = 7000 × 1.015^16

A = $8882.9

7 0
2 years ago
If f(x)=8x and g(x)=2x+1, what is (f×g)(x)
Sav [38]

Answer:

(f * g)(x) has a final product of 16x² + 8x.

Step-by-step explanation:

When you see (f * g)(x), this means that we are going to be multiply f(x) and g(x) together.

<em>f(x)=8x</em>

<em>g(x)=2x+1</em>

Now, we multiply these terms together.

(8x)(2x + 1)

Use the foil method to multiply.

16x² + 8x

So, the product of these terms is 16x² + 8x.

5 0
2 years ago
(+7) x (-3) math intergers
IrinaK [193]

Answer:

-21

Step-by-step explanation:

- * + = -

- * - = +

+ * + = +

Here + * - = -

7* 3 = 21 and sign is -ve

4 0
2 years ago
Read 2 more answers
Groupon is offering a discount on concert tickets to go see your favorite artist. The original price of the tickets are 75$ each
mezya [45]

Answer:

you'll save $18.75, the total being $56.25

Step-by-step explanation:

3 0
3 years ago
Since an instant replay system for tennis was introduced at a major​ tournament, men challenged 1406 referee​ calls, with the re
erastova [34]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for men and women players. The population proportions of men and women challenges for calls would be p1 and p2

P1 - P2 = difference in the proportion of men and women challenges for calls.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 ≠ p2

p1 - p2 ≠ 0

it is a two tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For old dough

x1 = 416

n1 = 1406

P1 = 416/1406 = 0.3

For new dough,

x2 = 217

n2 = 778

P2 = 217/778 = 0.28

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (416 + 217)/(1406 + 778) = 0.29

1 - pc = 1 - 0.29 = 0.71

z = (P1 - P2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.3 - 0.28)/√(0.29)(0.71)(1/1406 + 1/778) = 0.02/√0.00553857907

z = 0.99

Since it is a two tailed test, the curve is symmetrical. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score to the left of 0.99 is 1 - 0.84 = 0.16

We would double this area to include the area in the left tail of z = - 0.99 Thus

p = 0.16 × 2 = 0.32

Since 0.1 < 0.5, we would accept the null hypothesis.

p value = 0.337

Since 0.05 < 0.32, we would accept the null hypothesis

7 0
3 years ago
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