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Oksana_A [137]
2 years ago
7

Please SHOW WORK, will mark brainlist if correct

Mathematics
1 answer:
riadik2000 [5.3K]2 years ago
5 0

Answer:

\huge\boxed{\sf \frac{x+3}{x-3}}

Step-by-step explanation:

\displaystyle = \frac{x+7}{x^2+4x-21} \div \frac{x+5}{x^2+8x+15} \\\\Apply \ mid-term \ break\\\\= \frac{x+7}{x^2 +7x-3x-21} \div \frac{x+5}{x^2 +3x+5x+15} \\\\= \frac{x+7}{x(x+7)-3(x+7)} \div \frac{x+5}{x(x+3)+5(x+3)} \\\\Taking \ (x+3) \ and \ (x+7) \ common\\\\= \frac{x+7}{(x-3)(x+7)} \div \frac{x+5}{(x+3)(x+5)} \\\\= \frac{1}{x-3} \div \frac{1}{x+3} \\\\= \frac{1}{x-3} * (x+3)\\\\= \frac{x+3}{x-3} \\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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