Let the number of raspberry bushes in one garden = x
And the number of raspberry bushes in second garden = y
Garden one has 5 times as many raspberry bushes as second garden,
So the equation will be,
x = 5y -------(1)
If 22 bushes were transplanted from garden one to the second, number of bushes in both the garden becomes same,
Therefore, (x - 22) = (y + 22)
x - y = 22 + 22
x - y = 44 ------(2)
Substitute the value of x from equation (1) to equation (2)
5y - y = 44
4y = 44
y = 11
Substitute the value of 'y' in equation (1),
x = 5(11)
x = 55
Therefore, Number of bushes in garden one were 55 and in second garden 11 originally.
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Answer:
correct answer is 2
............................
A=54. And 24+30=54. So the answer is A
F''(x)=-2+36x-12x^2, f(0)=2, f'(0)=18
f'(x)=-2x+18x^2-4x^3+c
f'(0)=-2(0)+18(0)^2-4(0)^3+c=18
f'(0)=18x^2-4x^3-2x+18
f(x)=6x^3-x^4-x^2+18x+c
f(0)=6(0)^3-(0)^4-(0)^2+18(0)+c=2
f(x)=6x^3-x^4-x^2+18x+2
