A:
(f+g)(x)=f(x)+g(x)
(f+g)(x)=4x-5+3x+9
(f+g)(x)=7x+4
B:
(f•g)(x)=f(x)•g(x)
(f•g)(x)=(4x-5)(3x+9)
(f•g)(x)=12x^2-15x+36x-45
(f•g)(x)=12x^2+21x-45
C:
(f○g)(x)=f(g(x))
(f○g)(x)=4(3x+9)-5
(f○g)(x)=12x+36-5
(f○g)(x)=12x+31
Idk if she's too young to learn cross multiply, but this is an easier method.
Multiply everything by 4 which cancels out the 4 on the left side.
36z-16/5 <= 7z + 2
Now multiply everything by 5, cancelling out the right side 5.
36z-16 <= 35z + 10
Solve the equation normally
z-16<=10
z<=36
Answer:
7
Step-by-step explanation:
Simply subtract 6 from 13.
13-6=7
Hope this helps! :)
72 is a number between 67 and 113 that is a multiple of 3, 4, and 9.
72/3= 24
72/4= 18
72/9= 8