Question

10 Use the quadratic formula to solve the following. x^2+ 4x - 3=0

Answer 1

Answer:$x=-2+or-\sqrt{7}$

Step-by-step explanation:

$x^{2} +4x-3=0$

$x=\frac{-b+or-\sqrt{b^{2} -4ac} }{2a}$

$x=\frac{-4 + or - \sqrt{4^{2}-4(1)(-3) } }{2(1)\\}\\x= -4+or-\sqrt{16+12}/2\\x=-4+or-\sqrt{28} /2\\x=-4+or-\sqrt{4*7} /2\\x=-4+or- 2\sqrt{7} /2\\x=-2+or-\sqrt{7}$